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NDA · Maths · Applications of Integration
NDA Applications of Integration — Formulas 1
Question
1
of 13
1.
For a step curve
y
=
[
x
]
y = [x]
y
=
[
x
]
holding the single value
n
n
n
across an interval, what is the area under it?
A
A
=
n
×
(
interval width
)
A = n \times (\text{interval width})
A
=
n
×
(
interval width
)
B
A
=
1
2
∣
n
∣
×
(
interval width
)
A = \tfrac{1}{2}|n| \times (\text{interval width})
A
=
2
1
∣
n
∣
×
(
interval width
)
C
A
=
∣
n
∣
×
(
interval width
)
A = |n| \times (\text{interval width})
A
=
∣
n
∣
×
(
interval width
)
D
A
=
∣
n
∣
+
(
interval width
)
A = |n| + (\text{interval width})
A
=
∣
n
∣
+
(
interval width
)
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