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NDA · Maths · Trigonometric Identities
NDA Trigonometric Identities — Formulas 1
Question
1
of 13
1.
Which double-angle formula for sin 2A is correct?
A
sin
2
A
=
2
sin
A
cos
A
\sin 2A=2\sin A\cos A
sin
2
A
=
2
sin
A
cos
A
B
sin
2
A
=
cos
2
A
−
sin
2
A
\sin 2A=\cos^2 A-\sin^2 A
sin
2
A
=
cos
2
A
−
sin
2
A
C
sin
2
A
=
2
cos
2
A
−
1
\sin 2A=2\cos^2 A-1
sin
2
A
=
2
cos
2
A
−
1
D
sin
2
A
=
sin
A
cos
A
\sin 2A=\sin A\cos A
sin
2
A
=
sin
A
cos
A
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