Question Bank
BankGuidesNotes
Sign in

Filtered questions

106 questions match

Filtering by:
ChaptersAll

Pick a subject to see chapters

SubtopicsAll

Pick at least one chapter

All
  • Set · 2 questions
    Consider the following for the next two (02) items that follow: Let f(x)=sin⁡[π2]x+cos⁡[−π2]xf(x)=\sin[\pi^{2}]x+\cos[-\pi^{2}]xf(x)=sin[π2]x+cos[−π2]x where [⋅][\cdot][⋅] is a greatest integer function.
    • Q51
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q79 · Apr · 2023]
    • Q52
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q80 · Apr · 2023]
  • Set · 2 questions
    Consider the following for the next two (02) items that follow: Let I=∫ab∣x∣x dxI=\int_{a}^{b}\dfrac{|x|}{x}\,dxI=∫ab​x∣x∣​dx, a<ba<ba<b.
    • Q53
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q84 · Apr · 2023]
    • Q54
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q85 · Apr · 2023]
  • Set · 3 questions
    Consider the following for the next three (03) items that follow: Let f(x)=∣ln⁡x∣, x≠1f(x)=|\ln x|,\, x\neq1f(x)=∣lnx∣,x=1.
    • Q55
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q86 · Apr · 2023]
    • Q56
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q87 · Apr · 2023]
    • Q57
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q88 · Apr · 2023]
  • Set · 2 questions
    Consider the following for the next two (02) items that follow: Let f(x)={x+6,x≤1px+q,1<x<25x,x≥2f(x)=\begin{cases}x+6, & x\leq1\\px+q, & 1<x<2\\5x, & x\geq2\end{cases}f(x)=⎩⎨⎧​x+6,px+q,5x,​x≤11<x<2x≥2​ and f(x)f(x)f(x) is continuous.
    • Q58
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q89 · Apr · 2023]
    • Q59
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q90 · Apr · 2023]
  • Q60
    Lever: Modulus / absolute value behaviour

    Tap an option to check your answer.

    [Q97 · Apr · 2023]
  • Q61
    Lever: Modulus / absolute value behaviour

    Tap an option to check your answer.

    [Q99 · Apr · 2023]
  • Q62
    Lever: Modulus / absolute value behaviour

    Tap an option to check your answer.

    [Q74 · Apr · 2026]
  • Set · 2 questions
    For the next two (02) items that follow: Let f(x)={ax(x−1),x<1x−1,1≤x≤3px2+qx+2,x>3f(x)=\begin{cases}ax(x-1), & x<1\\ x-1, & 1\leq x\leq3\\ px^2+qx+2, & x>3\end{cases}f(x)=⎩⎨⎧​ax(x−1),x−1,px2+qx+2,​x<11≤x≤3x>3​. Given that f(x)f(x)f(x) is continuous for all x but not differentiable at x=1. Further f′(x)f'(x)f′(x) is continuous at x=3.
    • Q63
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q95 · Apr · 2026]
    • Q64
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q96 · Apr · 2026]
  • Set · 2 questions
    For the next two (02) items that follow: Let f(x)=tan⁡(x2)f(x)=\tan(x^2)f(x)=tan(x2) and g(x)=x∣x∣g(x)=x|x|g(x)=x∣x∣ for ∣x∣<π/2|x|<\sqrt{\pi/2}∣x∣<π/2​.
    • Q65
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q99 · Apr · 2026]
    • Q66
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q100 · Apr · 2026]
  • Q67
    Lever: Modulus / absolute value behaviour

    Tap an option to check your answer.

    [Q43 · Sep · 2025]
  • Set · 2 questions
    For the following two (02) items: Let f(x)={1−cos⁡2xx2,x<09,x=0x(16+x)−4,x>0f(x)=\begin{cases}\dfrac{1-\cos2x}{x^2}, & x<0\\ 9, & x=0\\ \dfrac{\sqrt{x}}{\sqrt{(16+\sqrt{x})}-4}, & x>0\end{cases}f(x)=⎩⎨⎧​x21−cos2x​,9,(16+x​)​−4x​​,​x<0x=0x>0​
    • Q68
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q71 · Sep · 2025]
    • Q69
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q72 · Sep · 2025]
  • Set · 2 questions
    For the following three (03) items: Consider the function f(x)=x∣x∣f(x)=x|x|f(x)=x∣x∣.
    • Q70
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q73 · Sep · 2025]
    • Q71
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q75 · Sep · 2025]
  • Set · 2 questions
    For the following two (02) items: Consider the function f(x)={4(5x),x<08k+x,x≥0f(x)=\begin{cases}4(5^x), & x<0\\ 8k+x, & x\geq0\end{cases}f(x)={4(5x),8k+x,​x<0x≥0​.
    • Q72
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q83 · Sep · 2025]
    • Q73
      Lever: Modulus / absolute value behaviour

      Tap an option to check your answer.

      [Q84 · Sep · 2025]
  • Set · 2 questions
    For the following two (02) items: Let the function f(x)=∣x−3∣+∣x−4∣f(x)=|x-3|+|x-4|f(x)=∣x−3∣+∣x−4∣ be defined on the interval [0,5][0,5][0,5].
    • Q74
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q87 · Sep · 2025]
    • Q75
      Lever: Differentiability at a point

      Tap an option to check your answer.

      [Q88 · Sep · 2025]
PrevPage 3 of 5Next
12345

From the team at LWS Pune — free for teachers.

NDA Maths GuideNDA English GuideNDA Physics GuideNDA Chemistry GuideNDA Biology GuideNDA Geography GuideNDA History GuideNDA Polity GuideNDA Economics GuideNDA Current Affairs GuideNDA Maths NotesNDA Physics NotesMHT-CET Maths NotesReport a questionGitHub
Question Bank
BankGuidesNotes
Sign in