NDA Maths · Functions

Domain, Range, and the Standard Properties

Find where a function is allowed to live (domain), what values it produces (range), and whether it is even, odd, or periodic.

Why this matters

The biggest slice of the chapter — 48 PYQs, and most are EASY or MODERATE. The recurring asks are narrow and learnable: domain from square-roots / denominators / logs, range of a bounded rational or quadratic-on-an-interval, even-vs-odd, and period. A few standard functions (modulus, reciprocal, sign, exponential) show up again and again. Drill these and you bank the chapter's easy marks.

Concept 1 of 7

Reading domain and range from a graph

Intuition

On a graph, the domain is the shadow the curve casts on the x-axis (how far left–right it extends) and the range is its shadow on the y-axis (how far up–down). Sweep across, then sweep up.

Definition

Domain == set of xx-values the graph covers; range == set of yy-values it reaches. A filled dot / solid edge includes the endpoint (closed); an open dot / asymptote excludes it (open). Reading them off a sketch is often faster than algebra for standard curves.

xy−222Domain [−2, 2] (x-shadow) · Range [0, 2] (y-shadow)

Worked example

The graph of ff is the upper semicircle of radius 2 centred at the origin. Domain and range?
  1. Horizontally the semicircle runs from 2-2 to 22: domain [2,2][-2,2].
  2. Vertically it runs from 00 (the ends) up to 22 (the top): range [0,2][0,2].
Answer:Domain [2,2][-2,2], range [0,2][0,2].
Practice this concept4 quick reps

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Domain read off a graph spanning x[1,3]x\in[-1,3]?
  2. 2.
    An open dot at an endpoint means the value is …?
  3. 3.
    Range of a horizontal line y=4y=4?
  4. 4.
    Domain shadow is cast on which axis?

Concept 2 of 7

Finding the domain (roots, denominators, logs)

Intuition

The domain is everything you are allowed to feed in. Three rules cover almost every NDA question: don't divide by zero, don't take an even root of a negative, and only take logs of positives. Apply each restriction and intersect.

Definition

  • Even root g(x)even\sqrt[\text{even}]{g(x)}: need g(x)0g(x)\ge 0.
  • Denominator: need denominator 0\neq 0.
  • Logarithm logg(x)\log g(x): need g(x)>0g(x)>0; base must be >0,1>0,\neq1.

When several appear, the domain is the intersection of all the individual conditions.

Worked example

Find the domain of f(x)=15xf(x)=\dfrac{1}{\sqrt{5-x}}.
  1. Square root needs 5x0x55-x\ge 0\Rightarrow x\le 5.
  2. But it sits in a denominator, so it must be 0\neq 0: 5x>0x<55-x>0\Rightarrow x<5 (strict).
  3. Combine: x<5x<5.
Answer:Domain =(,5)=(-\infty,5).
Practice this conceptself-check

Try it yourself

Find the domain of f(x)=x+1x3f(x)=\dfrac{\sqrt{x+1}}{x-3}.

From the bank · past-year question

Example 2FunctionsMODERATE
The domain of the function f(x)=(2x)(x3)f(x)=\sqrt{(2-x)(x-3)} is

[Q80 · Apr · 2019]

≥ 0 under a plain root, but > 0 when the root is a denominator

A root by itself allows equality (g\sqrt{g} needs g0g\ge0). The moment that root is in a denominator — e.g. 1xx\dfrac{1}{\sqrt{|x|-x}} — the value 0 is banned too, so you need the strict inequality g>0g>0. Missing this flips a closed bracket to an open one and loses the mark.

Concept 3 of 7

Finding the range

Intuition

The range is the set of outputs. For bounded rationals, solve for xx in terms of yy and ask which yy keep xx real; for a quadratic on an interval, use the vertex and endpoints; for sine/cosine combinations, bound the amplitude.

Definition

Common techniques:

  • **Solve for xx**: rearrange y=f(x)y=f(x) to x=x=\dots; the range is the yy for which xx is real/in-domain.
  • Quadratic on an interval: check the vertex and the endpoints; mind whether endpoints are included.
  • **asinx+bcosx+ca\sin x+b\cos x+c** lies in [ca2+b2,c+a2+b2][c-\sqrt{a^2+b^2},\,c+\sqrt{a^2+b^2}].

Worked example

Find the range of f(x)=11+x2f(x)=\dfrac{1}{1+x^2}, xRx\in\mathbb{R}.
  1. 1+x211+x^2\ge 1, and it grows without bound as x|x|\to\infty.
  2. So the denominator runs over [1,)[1,\infty), hence f=11+x2f=\dfrac{1}{1+x^2} runs over (0,1](0,1].
  3. Max 11 at x=0x=0 (attained); 00 is approached but never reached.
Answer:Range =(0,1]=(0,1].
Practice this conceptself-check

Try it yourself

Find the range of f(x)=x24x+5f(x)=x^2-4x+5 on the open interval (1,4)(1,4).

From the bank · past-year question

Example 3FunctionsMODERATE
For f(x)=x21+x2f(x)=\frac{x^2}{1+x^2}, what is the range?

[Q72 · Apr · 2018]

Range is not the codomain

If a question declares f:RRf:\mathbb{R}\to\mathbb{R} but the outputs only fill [0,1)[0,1), the range is [0,1)[0,1) — not R\mathbb{R}. 'Onto' questions are really 'shrink the codomain to the range' questions.

Concept 4 of 7

Even and odd functions

Intuition

An even function is mirror-symmetric about the y-axis (f(x)=f(x)f(-x)=f(x)); an odd function has half-turn symmetry about the origin (f(x)=f(x)f(-x)=-f(x)). Most functions are neither — only special ones qualify.

Definition

  • Even: f(x)=f(x)f(-x)=f(x) for all xx (e.g. x2, cosx, xx^2,\ \cos x,\ |x|).
  • Odd: f(x)=f(x)f(-x)=-f(x) for all xx (e.g. x3, sinx, xx^3,\ \sin x,\ x). An odd function defined at 0 has f(0)=0f(0)=0.
  • Test by computing f(x)f(-x) and comparing. If it matches neither, the function is neither.
Even: f(−x)=f(x)mirror across y-axisOdd: f(−x)=−f(x)half-turn about origin

Worked example

Classify f(x)=x3xf(x)=x^3-x as even, odd, or neither.
  1. Compute f(x)=(x)3(x)=x3+xf(-x)=(-x)^3-(-x)=-x^3+x.
  2. Factor: x3+x=(x3x)=f(x)-x^3+x=-(x^3-x)=-f(x).
  3. Matches the odd condition f(x)=f(x)f(-x)=-f(x).
Answer:Odd.
Practice this conceptself-check

Try it yourself

Classify f(x)=xx3f(x)=|x|-x^3.

From the bank · past-year question

Example 4FunctionsMODERATE
If f(x)=ln(x+1+x2)f(x) = \ln(x+\sqrt{1+x^2}), then which one of the following is correct?

[Q83 · Sep · 2022]

f(0)=0f(0)=0 is necessary for odd, not sufficient

Many odd functions pass through the origin, but passing through the origin does not make a function odd — you must verify f(x)=f(x)f(-x)=-f(x) for all xx. And a sum like even + odd is usually neither.

Concept 5 of 7

Periodic functions and their period

Intuition

A periodic function repeats: its graph is one tile copied endlessly. The period is the width of the smallest tile. For combinations you scale the base period, then take the LCM.

Definition

ff is periodic with period T>0T>0 if f(x+T)=f(x)f(x+T)=f(x) for all xx; the smallest such TT is the period.

  • sinx,cosx\sin x,\cos x: period 2π2\pi; tanx\tan x: period π\pi.
  • sin(kx)\sin(kx) has period 2πk\tfrac{2\pi}{|k|}; sin2x\sin^2 x has period π\pi.
  • Period of a sum is the LCM of the individual periods.

Period after scaling the argument

period of sin(kx)=2πk,period of tan(kx)=πk\text{period of }\sin(kx)=\frac{2\pi}{|k|},\qquad \text{period of }\tan(kx)=\frac{\pi}{|k|}

Worked example

Find the period of f(x)=cos ⁣(x2)f(x)=\cos\!\left(\dfrac{x}{2}\right).
  1. cos(kx)\cos(kx) has period 2πk\dfrac{2\pi}{|k|}; here k=12k=\tfrac12.
  2. Period =2π1/2=4π=\dfrac{2\pi}{1/2}=4\pi.
Answer:4π4\pi.
Practice this conceptself-check

Try it yourself

Find the period of f(x)=sin2x+cos3xf(x)=\sin 2x+\cos 3x.

From the bank · past-year question

Example 5FunctionsEASY
What is the period of the function f(x)=ln(2+sin2x)f(x)=\ln(2+\sin^{2}x)?

[Q23 · Sep · 2021]

Concept 6 of 7

The modulus function and distance

Intuition

x|x| measures distance from 0, so it is never negative and its V-shaped graph bounces off the x-axis at the origin. Sums of moduli like xa+xb|x-a|+|x-b| read as total distance to two points — minimised anywhere between them.

Definition

x=x|x|=x for x0x\ge0 and x-x for x<0x<0; it is even, with range [0,)[0,\infty).

  • x+x=0x+|x|=0 for x<0x<0 and 2x2x for x0x\ge0 — range [0,)[0,\infty).
  • xa+xb|x-a|+|x-b| (with a<ba<b) has minimum value bab-a, attained for all x[a,b]x\in[a,b].

Worked example

Find the minimum value of f(x)=x1+x5f(x)=|x-1|+|x-5|.
  1. Read it as the total distance from xx to 11 and to 55.
  2. That total is smallest when xx lies between them; then it equals the gap 51=45-1=4.
  3. (For xx outside [1,5][1,5] the total only grows.)
Answer:Minimum value =4=4, attained for all x[1,5]x\in[1,5].

From the bank · past-year question

Example 6FunctionsEASY
What is the range of the function f(x)=x+xf(x)=x+|x| if the domain is the set of real numbers?

[Q97 · Apr · 2023]

x|x| is even, never odd

x=x|-x|=|x|, so the modulus is even. Combinations like xx3|x|-x^3 mix an even and an odd part and end up neither. Also: x2=x\sqrt{x^2}=|x|, not xx — a common sign slip.

Concept 7 of 7

Standard functions and their graphs

Intuition

A handful of standard shapes recur: the reciprocal 1/x1/x (two branches, asymptotes), the sign function x/xx/|x| (a step of ±1\pm1), and the exponential axa^x (domain all reals, positive output). Knowing each one's domain, range and asymptotes answers most graph questions on sight.

Definition

  • Reciprocal 1xa\dfrac{1}{x-a}: domain xax\neq a, range y0y\neq0; vertical asymptote x=ax=a, horizontal y=0y=0.
  • Sign xx\dfrac{x}{|x|}: equals +1+1 for x>0x>0, 1-1 for x<0x<0; undefined at 0.
  • Exponential ax(a>0)a^x\,(a>0): domain R\mathbb{R}, range (0,)(0,\infty), continuous and differentiable everywhere.

Worked example

State the domain, range and asymptotes of f(x)=1x+2f(x)=\dfrac{1}{x+2}.
  1. Denominator zero at x=2x=-2: domain R{2}\mathbb{R}\setminus\{-2\}.
  2. It never outputs 0: range R{0}\mathbb{R}\setminus\{0\}.
  3. Vertical asymptote x=2x=-2; horizontal asymptote y=0y=0.
Answer:Domain x2x\neq-2, range y0y\neq0; asymptotes x=2x=-2 and y=0y=0.
Practice this concept4 quick reps

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Domain of 3x3^x?
  2. 2.
    Range of 10x10^x?
  3. 3.
    Value of xx\dfrac{x}{|x|} at x=4x=-4?
  4. 4.
    Vertical asymptote of 1x1\dfrac{1}{x-1}?

From the bank · past-year question

Example 7FunctionsMODERATE
Which one of the following is correct in respect of the graph of y=1x1y=\frac{1}{x-1}?

[Q98 · Apr · 2020]

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (1)

  • Periodic functions and their period

    Period after scaling the argument

    period of sin(kx)=2πk,period of tan(kx)=πk\text{period of }\sin(kx)=\frac{2\pi}{|k|},\qquad \text{period of }\tan(kx)=\frac{\pi}{|k|}

Watch out for (4)

Mastery check — 5 interleaved questions

Try each one before clicking. Questions are interleaved across the concepts above, not grouped — interleaving sharpens transfer.

Example 1FunctionsEASY
What is the domain of the function f(x)=1(x1)2f(x)=\sqrt{1-(x-1)^2}?

[Q59 · Apr · 2022]

Example 2FunctionsMODERATE
A mapping f:ABf:A\to B defined as f(x)=2x+33x+5f(x)=\dfrac{2x+3}{3x+5}, xAx\in A. If ff is to be onto, then what are AA and BB equal to?

[Q22 · Apr · 2023]

Example 3FunctionsHARD
Let f(t)=ln ⁣(t+1+t2)f(t)=\ln\!\left(t+\sqrt{1+t^2}\right) and g(t)=tan(f(t))g(t)=\tan(f(t)). Consider the following statements: A. f(t)f(t) is an odd function. B. g(t)g(t) is an odd function. Which of the statements given above is/are correct?

[Q93 · Sep · 2024]

Example 4FunctionsMODERATE
Directions for the following three (03) items : Read the following information and answer the three items that follow : Consider the function f(x)=g(x)+h(x)f(x) = g(x) + h(x) where g(x)=sin(x4)g(x) = \sin\left(\dfrac{x}{4}\right) and h(x)=cos(4x5)h(x) = \cos\left(\dfrac{4x}{5}\right).
What is the period of the function f(x)f(x) ?

[Q88 · Sep · 2019]

Example 5FunctionsMODERATE
Which is correct for f:RR+f:\mathbb{R}\to\mathbb{R}^+ defined as f(x)=x+1f(x)=|x+1|?

[Q71 · Apr · 2018]

Drill every past-year question on this subtopic

48 questions from the bank — paginated, with cart and Word-export support.