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IMAT Mathematics · Formula sheet

Geometry formulas

11 formulas, 3 reference tables and 16 common traps for IMAT Mathematics Geometry, grouped by subtopic.

Full notes with worked examples

Angles, Triangles and Polygons

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Triangles: angle sum, Pythagoras and special right triangles

Pythagoras and triangle area

a2+b2=c2A=12bha^2 + b^2 = c^2 \qquad A = \tfrac{1}{2}bh
  • a,ba, bthe two legs, which meet at the right angle
  • ccthe hypotenuse
  • b,hb, hin the area formula: a base and the height perpendicular to it

Congruent and similar triangles

Similar triangles

a′a=b′b=c′c=kArea′Area=k2\frac{a'}{a} = \frac{b'}{b} = \frac{c'}{c} = k \qquad \frac{\text{Area}'}{\text{Area}} = k^2
  • a,b,ca, b, csides of one triangle
  • a′,b′,c′a', b', c'the matching sides of the other
  • kkscale factor

Polygons: interior and exterior angles

Polygon angles

Sint=(n−2)×180∘regular: each exterior=360∘nS_{\text{int}} = (n - 2) \times 180^\circ \qquad \text{regular: each exterior} = \frac{360^\circ}{n}
  • nnnumber of sides

Angle facts for crossing lines and parallel lines

SituationFact
Angles on a straight lineAdd up to 180∘180^\circ
Angles around a pointAdd up to 360∘360^\circ
Vertically opposite angles, where two lines crossAre equal
Corresponding angles on parallel linesAre equal
Alternate angles on parallel linesAre equal
Co-interior angles on parallel linesAdd up to 180∘180^\circ
Co-interior angles are supplementary, not equal.

Common traps

Only parallel lines give equal alternate and corresponding angles

The equal-angle facts need the two lines to be parallel. If a diagram does not say so (arrows on the lines or words in the question), you cannot assume it, even if the lines look parallel.

The hypotenuse is the side opposite the right angle

In a2+b2=c2a^2 + b^2 = c^2, cc must be the longest side, facing the right angle. Adding the squares of a leg and the hypotenuse gives nonsense; when the hypotenuse is known, subtract: a2=c2−b2a^2 = c^2 - b^2.

Match the sides through the angles, not through their position on the page

In the cut-off triangle, AD matches AB (the whole side), not DB. Use AD/ABAD/AB, not AD/DBAD/DB, for the scale factor; the second ratio gives a wrong answer that is usually among the options.

Exterior angles total 360° for every polygon

The interior sum grows with the number of sides, but the exterior angles of any convex polygon add up to 360∘360^\circ. For a regular polygon, start from the exterior angle: it is the quickest route to nn.

Areas, Circles, Arcs and Circle Theorems

Learn this subtopic in the notes

Areas and perimeters of plane figures

Trapezium area

A=12(a+b) hA = \tfrac{1}{2}(a + b)\,h
  • a,ba, bthe two parallel sides
  • hhthe perpendicular distance between them

Circle measures: circumference, area, arcs and sectors

Arc and sector

arc=θ360×2πrsector=θ360×πr2\text{arc} = \frac{\theta}{360} \times 2\pi r \qquad \text{sector} = \frac{\theta}{360} \times \pi r^2
  • θ\thetaangle at the centre, in degrees
  • rrradius

Circle facts: chords, tangents and inscribed angles

FactStatement
Tangent and radiusA tangent is perpendicular to the radius at the point of contact
Two tangents from one pointHave equal lengths
Perpendicular from the centre to a chordBisects the chord
Angle at the centreIs twice the inscribed angle standing on the same arc
Angles in the same segmentInscribed angles on the same arc are equal
Angle in a semicircleAn inscribed angle standing on a diameter is 90∘90^\circ
Cyclic quadrilateralOpposite angles add up to 180∘180^\circ
Tangent and chord (alternate segment theorem)The angle between a tangent and a chord equals the inscribed angle on that chord in the other segment
They are equal: not complementary, not supplementary.

Common traps

Perimeter counts every side

A rectangle has two lengths and two widths, so its perimeter is 2(l+w)2(l + w). Setting l+wl + w equal to the perimeter gives a rectangle far too big, and its area is usually among the options.

Check whether you are given the radius or the diameter

A circle of diameter 10 has radius 5 and area 25π25\pi, not 100π100\pi. Using the diameter in πr2\pi r^2 makes the area four times too big.

The centre angle is double the edge angle, not half

On the same arc, the angle at the centre is the larger one: twice the inscribed angle. Halving the inscribed angle to get the centre angle reverses the theorem.

Solids: Surface Area, Volume and Scaling

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How area and volume scale with length

Scale factors

A2A1=k2V2V1=k3\frac{A_2}{A_1} = k^2 \qquad \frac{V_2}{V_1} = k^3
  • kkratio of matching lengths, large to small

Volume and surface area of the standard solids

SolidVolumeSurface area
Prism, cross-section area AA, length LLALALTwo end faces plus the rectangles round the side
Cuboid a×b×ca \times b \times cabcabc2(ab+bc+ca)2(ab + bc + ca)
Cylinder, radius rr, height hhπr2h\pi r^2 h2πr2+2πrh2\pi r^2 + 2\pi r h (curved part 2πrh2\pi r h)
Cone, radius rr, height hh, slant ll13πr2h\tfrac{1}{3}\pi r^2 hπr2+πrl\pi r^2 + \pi r l (curved part πrl\pi r l)
Sphere, radius rr43πr3\tfrac{4}{3}\pi r^34πr24\pi r^2
Pyramid, base area BB, height hh13Bh\tfrac{1}{3}BhBase plus the triangular faces

Common traps

A cone's volume uses the vertical height, not the slant height

V=13πr2hV = \tfrac{1}{3}\pi r^2 h needs the height measured straight up. If you are given the slant height, find hh with Pythagoras first. The slant height belongs only in the curved surface area πrl\pi r l.

Sphere: 4πr² for area, (4/3)πr³ for volume

The surface area of a sphere is 4πr24\pi r^2, with no 13\tfrac{1}{3}. Mixing the two formulas gives a wrong answer with the wrong units: area must come out in squared units, volume in cubed units.

Volume goes with the cube of the length

Doubling every length makes a solid 8 times as heavy, not 2 or 4 times. A percentage change in length must be cubed for volume and squared for area, never just multiplied by 3 or 2.

Distance, Midpoint, Gradient and Lines

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Distance and midpoint between two points

Distance and midpoint

d=(x2−x1)2+(y2−y1)2M=(x1+x22,y1+y22)d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \qquad M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)

Gradient and the equation of a straight line

Gradient and line through a point

m=y2−y1x2−x1y−y1=m(x−x1)m = \frac{y_2 - y_1}{x_2 - x_1} \qquad y - y_1 = m(x - x_1)

Parallel and perpendicular lines, and where lines meet

Parallel and perpendicular gradients

parallel: m1=m2perpendicular: m1m2=−1\text{parallel: } m_1 = m_2 \qquad \text{perpendicular: } m_1 m_2 = -1

Common traps

The midpoint uses sums, the distance uses differences

Average the coordinates for a midpoint: (x1+x2)/2(x_1 + x_2)/2. Half the difference, (x2−x1)/2(x_2 - x_1)/2, is how far the midpoint is from each end, not where it is.

Gradient is change in y over change in x

Rise over run: (y2−y1)/(x2−x1)(y_2 - y_1)/(x_2 - x_1). Putting the x-difference on top gives the reciprocal, which IMAT includes as an option. Subtract in the same order on top and bottom.

A perpendicular gradient needs both a flip and a sign change

The perpendicular to a line of gradient mm has gradient −1/m-1/m. Taking only the reciprocal (1/m1/m) or only the negative (−m-m) gives a line that is not perpendicular; both wrong versions appear among the options.

Equations of Circles and Parabolas

Learn this subtopic in the notes

Equation of a circle and completing the square

Circle with centre (a, b) and radius r

(x−a)2+(y−b)2=r2(x - a)^2 + (y - b)^2 = r^2
  • (a,b)(a, b)the centre
  • rrthe radius

The parabola y = ax² + bx + c: vertex, axis and where a line meets it

Vertex form

y=a(x−p)2+qvertex (p,q),axis x=py = a(x - p)^2 + q \qquad \text{vertex } (p, q), \quad \text{axis } x = p

Common traps

(x minus a) squared means the centre is at plus a

In (x+4)2+(y−5)2=9(x + 4)^2 + (y - 5)^2 = 9 the centre is (−4,5)(-4, 5), not (4,−5)(4, -5). And the right-hand side is r2r^2: here the radius is 3, not 9.

Divide through before reading off the centre

The rule centre =(−D/2,−E/2)= (-D/2, -E/2) only works when x2x^2 and y2y^2 have coefficient 1. If the equation starts 2x2+2y22x^2 + 2y^2, divide every term by 2 first.

Touching means a repeated root

A line touches a parabola when the combined quadratic has exactly one solution, which means a discriminant of zero. Two different roots mean the line cuts through at two points; no real roots mean it misses.

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