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IMAT Physics · Formula sheet

Heat and Thermodynamics formulas

9 formulas, 3 reference tables and 17 common traps for IMAT Physics Heat and Thermodynamics, grouped by subtopic.

Full notes with worked examples

Temperature, Heat and How Heat Moves

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Temperature, heat and the Kelvin scale

Celsius to kelvin

T (K)=θ (∘C)+273T\,(\text{K}) = \theta\,(^\circ\text{C}) + 273
  • TTabsolute temperature, in K
  • θ\thetatemperature in degrees Celsius

Thermal expansion of solids and liquids

Linear expansion

ΔL=αL0ΔT\Delta L = \alpha L_0 \Delta T
  • ΔL\Delta Lincrease in length, in m
  • α\alphacoefficient of linear expansion, in K⁻¹
  • L0L_0original length, in m
  • ΔT\Delta Ttemperature rise, in K (or °C)

Heat transfer: conduction, convection and radiation

MechanismHow the energy movesNeeds a medium?Everyday example
ConductionVibrating particles and free electrons pass energy to neighboursYes; works best in solids, especially metalsThe handle of a metal pan getting hot
ConvectionWarm, less dense fluid rises and cooler fluid sinks, forming a currentYes; only liquids and gasesWarm air rising above a radiator
RadiationElectromagnetic waves, mainly infraredNo; it crosses a vacuumSunlight warming the Earth through space

Common traps

A temperature change is not converted by adding 273

Adding 273 converts a temperature reading. A difference of 50 °C is a difference of 50 K, because the two scales have the same step size. Options that add 273 to a temperature rise are wrong.

Heat and temperature are different quantities

Temperature is an average per particle; heat is energy that moves. A large cool lake holds far more internal energy than a small hot spark. Statements treating a body as containing heat, or temperature as an amount of energy, are wrong.

Feeling colder does not mean a lower temperature

Objects left in the same room reach the same temperature. Metal feels colder than wood because it conducts energy out of your skin faster, not because it is cooler.

Water does not always expand when heated

Between 0 °C and 4 °C water contracts as it warms, and it is densest at about 4 °C. Options claiming every liquid expands on heating at every temperature, or that water is densest at 0 °C, are wrong.

Specific Heat, Latent Heat and Mixing

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Specific heat capacity: the energy to warm a mass

Heating without a change of state

Q=mcΔTQ=PtQ = m c \Delta T \qquad Q = P t
  • QQenergy supplied, in J
  • mmmass, in kg
  • ccspecific heat capacity, in J kg⁻¹ K⁻¹
  • ΔT\Delta Ttemperature change, in K
  • P, tP,\ theater power in W, and time in s

Latent heat and changes of state

Energy for a change of state

Q=mLQ = m L
  • QQenergy absorbed or released, in J
  • mmmass that changes state, in kg
  • LLspecific latent heat, in J kg⁻¹

Calorimetry: heat lost equals heat gained

Mixing in an insulated container

m1c1(T1−T)=m2c2(T−T2)m_1 c_1 (T_1 - T) = m_2 c_2 (T - T_2)
  • m1,c1,T1m_1, c_1, T_1mass, specific heat and starting temperature of the hotter body
  • m2,c2,T2m_2, c_2, T_2the same for the colder body
  • TTthe shared final temperature

Common traps

Power times time needs seconds

A watt is a joule per second, so Q=PtQ = Pt gives joules only with tt in seconds. Leaving minutes in gives an answer 60 times too small, and that wrong value is usually one of the options.

Thermal conductivity is not specific heat capacity

Specific heat capacity says how much energy warms a kilogram; thermal conductivity says how fast heat passes through a material. A calorimetry calculation never needs the conductivity.

Melting breaks forces between molecules, not bonds inside them

When wax or ice melts, the energy overcomes the attractions between molecules. The covalent bonds within each molecule are untouched; breaking those would be a chemical change. Statements that melting breaks the bonds inside the molecules are wrong.

The temperature does not rise during a change of state

While a pure substance melts or boils, the energy supplied goes into the change of state and the temperature stays constant. A heating curve shows a flat section there, not a slope.

Melted ice must still warm up

When ice melts and the mixture ends above 0 °C, the meltwater also warms from 0 °C to the final temperature. The energy balance needs mLf+mcTm L_f + m c T on the gaining side, not mLfm L_f alone.

Ideal Gases and Kinetic Theory

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The ideal gas equation and the three gas laws

Ideal gas equation

pV=nRTp1V1T1=p2V2T2pV = nRT \qquad \frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}
  • pppressure, in Pa
  • VVvolume, in m³
  • nnamount of gas, in mol
  • RRgas constant, 8.31 J mol⁻¹ K⁻¹
  • TTabsolute temperature, in K

Kinetic theory: temperature and molecular speed

Mean kinetic energy of a molecule

Ek‾=12m⟨v2⟩=32kBT\overline{E_k} = \tfrac{1}{2} m \langle v^2 \rangle = \tfrac{3}{2} k_B T
  • mmmass of one molecule, in kg
  • ⟨v2⟩\langle v^2 \ranglemean of the squared speeds
  • kBk_BBoltzmann constant, 1.38 × 10⁻²³ J K⁻¹
  • TTabsolute temperature, in K

Common traps

Gas laws need kelvin, never Celsius

Proportions such as p∝Tp \propto T hold only for absolute temperature. Heating from 10 °C to 20 °C does not double the pressure; it raises it by about 3.5%, from 283 K to 293 K.

Boyle's law is not a straight line on a p against V graph

At constant temperature, p=constant/Vp = \text{constant}/V, a curve that falls ever less steeply. A straight line through the origin appears only when pp is plotted against 1/V1/V.

Heavier molecules do not have more kinetic energy

At the same temperature all gas molecules have the same mean kinetic energy, whatever their mass. The heavier ones simply move more slowly, with a smaller mean square speed.

The First Law and Gas Processes

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The first law of thermodynamics and the work done by a gas

First law and work at constant pressure

ΔU=Q−WW=p ΔV\Delta U = Q - W \qquad W = p\,\Delta V
  • ΔU\Delta Uchange in internal energy of the gas, in J
  • QQheat given to the gas, in J
  • WWwork done by the gas, in J
  • p, ΔVp,\ \Delta Vpressure in Pa, change in volume in m³

Isothermal, isobaric, isochoric and adiabatic processes

ProcessWhat stays constantFirst law becomesLine on a p against V graph
IsothermalTemperature, so the internal energy of an ideal gasQ=WQ = WA hyperbola, pVpV constant
IsobaricPressureQ=ΔU+pΔVQ = \Delta U + p\Delta VA horizontal line
IsochoricVolume, so no work is doneQ=ΔUQ = \Delta UA vertical line
AdiabaticNo heat in or outΔU=−W\Delta U = -WA curve steeper than the isotherm through the same point

Common traps

Work done by the gas and work done on it have opposite signs

Compression means work is done on the gas, so the work done by the gas is negative. Putting 600 J of compression into ΔU=Q−W\Delta U = Q - W as +600+600 gives the internal energy change with the wrong sign.

Adiabatic does not mean constant temperature

Adiabatic means no heat flows. The temperature changes, because work changes the internal energy. Isothermal is the opposite case: the temperature is constant, and heat does flow in or out.

The Second Law, Entropy and Heat Engines

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Heat engines, efficiency and the Carnot limit

Efficiency and the Carnot limit

η=WQh=1−QcQhηmax⁡=1−TcTh\eta = \frac{W}{Q_h} = 1 - \frac{Q_c}{Q_h} \qquad \eta_{\max} = 1 - \frac{T_c}{T_h}
  • Qh, QcQ_h,\ Q_cheat taken from the hot reservoir, heat given to the cold one, in J
  • WWuseful work done, in J
  • Th, TcT_h,\ T_creservoir temperatures, in K

The second law and entropy

ProcessEntropy changeWhy
Ice meltingIncreasesAn ordered crystal becomes a disordered liquid
Liquid evaporatingIncreasesMolecules spread out into a much larger volume as gas
Friction slowing a sliding blockIncreasesOrdered motion becomes random thermal motion
Heat flowing from hot to coldIncreases overallThe cold body gains more entropy than the hot body loses
Frictionless swing of a pendulum in a vacuumClose to zeroNo energy is turned into heat, so the motion is reversible

Common traps

The Carnot formula needs kelvin

Putting Celsius temperatures into 1−Tc/Th1 - T_c/T_h gives a far too large efficiency. Convert both temperatures to kelvin first.

No real engine reaches the Carnot efficiency

The Carnot value is a ceiling for an ideal, reversible engine. Any claim that an engine beats it, or reaches 100% with a cold side above absolute zero, breaks the second law.

Entropy can fall locally

The second law is about the total entropy of an isolated system. A living cell, a freezer or a growing crystal can lower its own entropy, as long as it raises the entropy of its surroundings by more.

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