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SPI Mathematics · Formula sheet

Polynomials formulas

9 formulas, 2 reference tables and 18 common traps for SPI Mathematics Polynomials, grouped by subtopic.

Full notes with worked examples

Degree, Value and Zeroes of a Polynomial

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Value of a polynomial and what a zero is

Zero of a polynomial

p(a)=0zero of ax+b=−bap(a) = 0 \qquad \text{zero of } ax + b = -\frac{b}{a}

Degree of a polynomial and the name for each degree

NameDegreeExample
Constant polynomial07
Linear polynomial13x + 2
Quadratic polynomial2x² − 4x + 1
Cubic polynomial32x³ + x − 5
Biquadratic (quartic) polynomial4x⁴ − 5x² + 6
A biquadratic is a quadratic in x², so its degree is 4, not 2.
The same names are used for equations: a cubic equation has degree 3.

Reading the zeroes of a polynomial from its graph

What the graph doesNumber of distinct zeroes
A straight line crosses the x-axis once1
A parabola cuts the x-axis at two points2
A parabola only touches the x-axis at one point1
Touching counts: the point where it touches is a zero.
A parabola never meets the x-axis0
A cubic curve crosses the x-axis three times3
Count the meeting points with the x-axis, not with the y-axis.

Common traps

Taking the degree from the first term

The degree is the highest power anywhere in the polynomial. 2x−x3+42x - x^3 + 4 has degree 3, even though it starts with an x term.

Treating a root sign as a power of x

2\sqrt{2} is a constant and does not change the degree. x\sqrt{x} is x1/2x^{1/2}, which makes the expression not a polynomial.

Squaring after attaching the minus sign

At x=−2x = -2, the term −3x2-3x^2 is −3×4=−12-3 \times 4 = -12, not +12+12. Square the number first, then multiply by the coefficient with its sign.

Counting where the graph meets the y-axis

Zeroes are where the graph meets the x-axis. A curve that cuts the y-axis at 3 has p(0)=3p(0) = 3, which says nothing about its zeroes.

Missing a zero where the curve only touches

A parabola that just touches the x-axis and turns back still meets it there, so it has exactly one distinct zero, not none.

Factorising Polynomials

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Factorising a quadratic polynomial by splitting the middle term

Product of two brackets

(x+p)(x+q)=x2+(p+q)x+pq(x + p)(x + q) = x^2 + (p + q)x + pq

Factorising by grouping and by substitution

Grouping pattern

ax+ay+bx+by=a(x+y)+b(x+y)=(a+b)(x+y)ax + ay + bx + by = a(x + y) + b(x + y) = (a + b)(x + y)

Common traps

Checking only the product

(x+6)(x−4)(x + 6)(x - 4) and (x−6)(x+4)(x - 6)(x + 4) both give the constant −24-24. The middle term decides: the first gives +2x+2x, the second −2x-2x.

Comparing terms of different powers

Match the coefficient of x with the coefficient of x, and the constant with the constant. In x2+kx+8=(x+2)(x+4)x^2 + kx + 8 = (x + 2)(x + 4), k is 6, the x coefficient, not 8.

Taking out a positive factor from a negative pair

In x3−2x2−5x+10x^3 - 2x^2 - 5x + 10, take −5-5 out of the second pair: x2(x−2)−5(x−2)=(x−2)(x2−5)x^2(x - 2) - 5(x - 2) = (x - 2)(x^2 - 5). Taking out +5+5 leaves (−x+2)(-x + 2), which does not match.

Leaving the answer in t

After factorising in t, replace t by the bracket it stood for. (t−3)(3t+2)(t - 3)(3t + 2) with t=a+bt = a + b becomes (a+b−3)(3a+3b+2)(a + b - 3)(3a + 3b + 2).

Division Algorithm, Remainder and Factor Theorems

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The division algorithm for polynomials

Division algorithm

p(x)=g(x) q(x)+r(x),deg⁡r<deg⁡gdeg⁡q=deg⁡p−deg⁡gp(x) = g(x)\,q(x) + r(x), \quad \deg r < \deg g \qquad \deg q = \deg p - \deg g

The remainder theorem

Remainder theorem

remainder of p(x)÷(x−a)=p(a)\text{remainder of } p(x) \div (x - a) = p(a)

The factor theorem

Factor theorem

(x−a) is a factor of p(x) when p(a)=0(x - a) \text{ is a factor of } p(x) \text{ when } p(a) = 0

Common traps

Skipping a missing power

x3−7x+6x^3 - 7x + 6 has no x2x^2 term. Write it as x3+0x2−7x+6x^3 + 0x^2 - 7x + 6 before dividing, or the subtraction lines up the wrong columns.

Expecting a number as every remainder

The remainder only has to be of lower degree than the divisor. Divided by a quadratic, the remainder can be linear, such as 3x+13x + 1.

Putting in the wrong sign

For the divisor x+3x + 3, put x=−3x = -3, not x=3x = 3. The number you put in is the one that makes the divisor 0.

Mixing up the factor and the zero

The factor x+5x + 5 goes with the zero −5-5, and the factor x−5x - 5 with the zero 5. Test a factor by putting in the number that makes it 0.

Zeroes and Coefficients

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Sum and product of the zeroes of a quadratic polynomial

Zeroes of a quadratic polynomial

α+β=−baαβ=caα2+β2=(α+β)2−2αβ\alpha + \beta = -\frac{b}{a} \qquad \alpha\beta = \frac{c}{a} \qquad \alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta

Forming a quadratic polynomial from its zeroes

Quadratic from its zeroes

k[x2−(α+β)x+αβ]k\left[x^2 - (\alpha + \beta)x + \alpha\beta\right]

Zeroes and coefficients of a cubic polynomial

Zeroes of a cubic polynomial

α+β+γ=−baαβ+βγ+γα=caαβγ=−da\alpha + \beta + \gamma = -\frac{b}{a} \qquad \alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a} \qquad \alpha\beta\gamma = -\frac{d}{a}

Common traps

Dropping the minus in the sum

For 2x2+3x+42x^2 + 3x + 4, the sum of the zeroes is −32-\frac{3}{2} and the product 2, so 1α+1β=−34\frac{1}{\alpha} + \frac{1}{\beta} = -\frac{3}{4}, not 34\frac{3}{4}.

Reading signs from the product alone

A positive product says only that the zeroes share a sign. Look at the sum to tell whether both are positive or both are negative.

Thinking only one polynomial fits

x2−5x+4x^2 - 5x + 4, 2x2−10x+82x^2 - 10x + 8 and −x2+5x−4-x^2 + 5x - 4 all have the zeroes 1 and 4. An option that is a multiple of your answer is still right.

Adding instead of subtracting in a conjugate product

(3+2)(3−2)=9−2=7(3 + \sqrt{2})(3 - \sqrt{2}) = 9 - 2 = 7, not 9+29 + 2. The square of the root part is always subtracted.

Using the quadratic sign for a cubic product

For a quadratic the product of the zeroes is +ca+\frac{c}{a}, but for a cubic it is −da-\frac{d}{a}. The product of the zeroes of x3−2x+5x^3 - 2x + 5 is −5-5.

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