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SPI Physics · Formula sheet

Kinematics and Motion formulas

4 formulas, 2 reference tables and 11 common traps for SPI Physics Kinematics and Motion, grouped by subtopic.

Full notes with worked examples

Distance, Displacement and Speed

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Distance and displacement

displacement≤distancecircumference of a circle=2πr\text{displacement} \le \text{distance} \qquad \text{circumference of a circle} = 2\pi r

Average speed over two or more parts of a journey

Average speed

average speed=total distancetotal time1 km/h=518 m/s\text{average speed} = \frac{\text{total distance}}{\text{total time}} \qquad 1\ \text{km/h} = \frac{5}{18}\ \text{m/s}

Rest and motion depend on what you compare with

BodyAt rest compared withIn motion compared with
A passenger sitting in a moving busThe bus and the other passengersThe road and the trees outside
A tree by the roadThe groundA passenger in a passing bus
A pilot flying a planeThe planeThe ground
Answer 'rest or motion?' with both, once you name the two reference points.

Common traps

Picking only one of rest and motion

A body can be at rest and in motion at the same time, compared with two different things. When the options include 'both', that is the answer for a passenger in a moving vehicle.

Giving the arc length as the displacement

On a circular path the arc is the distance. The displacement is the straight chord from start to end: across the full width of the circle, it is the diameter, 2r.

Thinking a full round is far away

After one complete round the body is back where it began, so the displacement is zero, even though the distance is 2πr2\pi r.

Averaging the two speeds

When the times are different, the mean of the two speeds is wrong. Find the total distance and the total time first; only equal TIMES make the simple mean right.

Using minutes with km/h

15 minutes at 8 km/h is 8×14=28 \times \frac{1}{4} = 2 km, not 120 km. Turn minutes into hours (divide by 60) before multiplying.

Motion Graphs and Equations of Motion

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Slope and area of a velocity-time graph

Velocity-time graph

a=slope=v−utdistance=area under the grapha = \text{slope} = \frac{v - u}{t} \qquad \text{distance} = \text{area under the graph}

The three equations of motion and a body thrown upwards

Equations of motion

v=u+ats=ut+12at2v2=u2+2asu=2gh to reach height hv = u + at \qquad s = ut + \tfrac{1}{2}at^2 \qquad v^2 = u^2 + 2as \qquad u = \sqrt{2gh} \text{ to reach height } h
  • uustarting velocity
  • vvfinal velocity
  • aaacceleration
  • ssdistance (displacement)
  • tttime

What the shape of each motion graph means

GraphLine shapeWhat the motion is
Distance against timeFlatAt rest
Distance against timeStraight, sloping upConstant speed
Distance against timeCurving upwardsSpeeding up
Velocity against timeFlat (above zero)Constant velocity, so constant speed
Velocity against timeStraight, sloping upConstant acceleration, speed changing
Speed against timeStraight, sloping upSpeed rising steadily
Acceleration against timeFlat (above zero)Constant acceleration, speed changing
Constant speed shows up as a sloping distance-time line or a flat speed or velocity-time line.

Common traps

Reading a flat acceleration line as constant speed

A flat line on an acceleration-time graph means the acceleration is steady, so the speed is changing all the time. Constant speed needs zero acceleration.

Reading a flat distance-time line as constant speed

A flat distance-time line means the body is at rest. Constant speed on that graph is a straight line that slopes.

Mixing up slope and area

The slope of a velocity-time graph is the acceleration; the area under it is the distance. Area is never the acceleration.

Comparing two bodies by their speed at one moment

Which of two cars is ahead depends on the distance each has covered, which is the area under each graph up to that time, not on which one is faster at that instant.

Forgetting the speed at the top is zero

A body thrown up stops for an instant at its highest point. Put v = 0 there; that is what turns v2=u2−2ghv^2 = u^2 - 2gh into u=2ghu = \sqrt{2gh}.

Using the equations when acceleration changes

The three equations need steady acceleration. On a curved velocity-time graph, use the area and slope instead.

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