Principle deep dive
AM-GM / mean inequalities (incl. x + 1/x ≥ 2)
Whenever you need a minimum of a sum or maximum of a product under a constraint, AM-GM is the lever. Spans Sequence & Series, Application of Derivatives, Trig Identities and Logarithms; questions disguise the inequality across chapter lines.
- questions in the bank
- 31
- tagged HARD
- 16%
- chapter spread
- 6
- worked examples below
- 4
When to reach for it
You need a minimum of a sum or a maximum of a product, given a constraint on the other.
Why this principle matters
AM-GM is the lever most students reach for last. They start with calculus, set f'(x) = 0, lose to messy algebra, and then realise the answer was a one-line bound. The principle is simple: for positive reals, the arithmetic mean is at least the geometric mean, with equality when all values are equal.
The bank disguises this across 10 chapters. Sequence & Series asks for AP/GP relations. Application of Derivatives wraps it in 'find the minimum'. Trigonometric Identities asks for the max of sin·cos. Probability frames it as 'find x such that x + 1/x > 2'. The chapter changes; the inequality doesn't.
Internalise three patterns: (1) for positive x, x + 1/x ≥ 2 with equality at x = 1, (2) for fixed product xy, the sum x + y is minimised when x = y, (3) for fixed sum x + y, the product xy is maximised when x = y. From these you can derive most of the bank's AM-GM questions in under 60 seconds each.
4 worked examples from the bank
Each example demonstrates the principle on a real past-year question. Click to reveal the answer, then the solution.
[Q79 · Apr · 2022]
[Q87 · Apr · 2021]
[Q78 · Apr · 2026]
[Q91 · Sep · 2022]
Variants to recognise
Same principle, different surfaces. Pattern-match these on test day.
x + 1/x ≥ 2
For positive x. Generalises to xⁿ + 1/xⁿ ≥ 2 for any positive n.
Cauchy-Schwarz / power mean inequality
Generalisation: AM of pᵗʰ powers ≥ AM of qᵗʰ powers for p > q. NDA rarely needs this; AM-GM suffices.
Three-variable AM-GM
If abc = k, then a + b + c ≥ 3·k^(1/3). Equality at a = b = c = k^(1/3).
AM ≥ GM ≥ HM chain
For positive reals, AM ≥ GM ≥ HM with all three equal iff all values equal. Two more inequalities for free.
Drill every am-gm / mean inequalities (incl. x + 1/x ≥ 2) question
31 questions from the bank — paginated, with cart and Word-export support.
Related principles
Often combined with this one — drill these next if you found the examples above tractable.