PYQ Vault

Day 266: CBSE Class 12 Maths

5 questions (8 parts). Try each one first, then open its answer.

  1. Question 1 (case study, 4 parts)

    Probability. Asked once: 2023 (same type asked 5 times)

    Recent studies suggest that roughly 12% of the world population is left handed. Depending upon the parents, the chances of having a left handed child are as follows : A : When both father and mother are left handed : Chances of left handed child is 24%. B : When father is right handed and mother is left handed : Chances of left handed child is 22%. C : When father is left handed and mother is right handed : Chances of left handed child is 17%. D : When both father and mother are right handed : Chances of left handed child is 9%. Assuming that P(A)=P(B)=P(C)=P(D)=14P(A) = P(B) = P(C) = P(D) = \frac{1}{4} and L denotes the event that child is left handed. Based on the above information, answer the following questions :
    37 (i)
    Find P(L/C)P(L/C)
    37 (ii)
    Find P(L‾/A)P(\overline{L}/A)
    37 (iii)(a)
    Find P(A/L)P(A/L)
    37 (iii)(b)
    Find the probability that a randomly selected child is left handed given that exactly one of the parents is left handed.
  2. Question 2

    Probability. Asked once: 2023 (same type asked 5 times)

    12
    If P(AB)=0⋅3P\left(\frac{A}{B}\right) = 0{\cdot}3, P(A)=0⋅4P(A) = 0{\cdot}4 and P(B)=0⋅8P(B) = 0{\cdot}8, then P(BA)P\left(\frac{B}{A}\right) is equal to :

    Tap an option to check your answer.

  3. Question 3

    Continuity and Differentiability. Asked once: 2023 (same type asked 4 times)

    3
    If f(x)=2∣x∣+3∣sin⁡x∣+6f(x) = 2|x| + 3|\sin x| + 6, then the right hand derivative of f(x) at x=0x = 0 is :

    Tap an option to check your answer.

  4. Question 4

    Integrals. Asked once: 2022 (same type asked 4 times)

    12 (b)
    Evaluate : ∫−215−4x−x2 dx\int_{-2}^{1} \sqrt{5 - 4x - x^2} \, dx
  5. Question 5

    Linear Programming. Asked once: 2024 (same type asked 4 times)

    30
    Solve the following linear programming problem graphically : Maximise z=4x+3yz = 4x + 3y, subject to the constraints x+y≤800x + y \le 800 2x+y≤10002x + y \le 1000 x≤400x \le 400 x,y≥0x, y \ge 0.