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p sin^2 a + q cos^2 a = m: find tan^2 a

This type of question, asked 2 times: CDS 2 2025, CDS 1 2026. All 2 questions below, oldest first.

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  1. Question 1 (case study, 2 parts)

    CDS 2 2025

    Let psin⁡2α+qcos⁡2α=mp\sin^2\alpha + q\cos^2\alpha = m, qsin⁡2β+pcos⁡2β=nq\sin^2\beta + p\cos^2\beta = n; p≠m,np \ne m, n and q≠m,nq \ne m, n.
    41
    What is (tan⁡αtan⁡β)2\left(\dfrac{\tan\alpha}{\tan\beta}\right)^2 equal to?

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    42
    If α\alpha and β\beta are complementary angles, then which one of the following is correct?

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  2. Question 2 (case study, 2 parts)

    CDS 1 2026

    For the next two (02) items that follow : psin⁡2α+qcos⁡2α=mp\sin^2\alpha + q\cos^2\alpha = m and pcos⁡2β+qsin⁡2β=np\cos^2\beta + q\sin^2\beta = n
    95
    What is tan⁡2α\tan^2\alpha equal to ?

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    96
    What is cot⁡2β\cot^2\beta equal to ?

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