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Given ab + bc + ca = 0, write a^2 - bc = a(a + b + c) and simplify

This type of question, asked 2 times: CDS 2 2017, CDS 2 2018. All 2 questions below, oldest first.

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  1. Question 1

    CDS 2 2017

    32
    If ab+bc+ca=0ab + bc + ca = 0, then what is the value of a2a2−bc+b2b2−ca+c2c2−ab\frac{a^2}{a^2 - bc} + \frac{b^2}{b^2 - ca} + \frac{c^2}{c^2 - ab} ?

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  2. Question 2

    CDS 2 2018

    25
    If ab + bc + ca = 0, then the value of (b2−ca)(c2−ab)+(a2−bc)(c2−ab)+(a2−bc)(b2−ca)(a2−bc)(b2−ca)(c2−ab)\frac{(b^2 - ca)(c^2 - ab) + (a^2 - bc)(c^2 - ab) + (a^2 - bc)(b^2 - ca)}{(a^2 - bc)(b^2 - ca)(c^2 - ab)} is

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