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Day 11: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Organic Chemistry - Some Basic Principles and Techniques. This type asked 7 times: 2021 Paper 19, 27 Jun 2022, 1 Feb 2024, 8 Apr 2024, 9 Apr 2024, 22 Jan 2025, 24 Jan 2025. This one: 24 Jan 2025 See all 7 of this type

    122
    The possible number of stereoisomers for 5-phenylpent-4-en-2-ol is ____\_\_\_\_ .

  2. Question 2

    Some Basic Concepts of Chemistry. This type asked 7 times: 2021 Paper 16, 27 Jul 2022, 1 Feb 2023, 29 Jan 2024, 6 Apr 2024, 9 Apr 2024, 22 Jan 2025. This one: 22 Jan 2025 See all 7 of this type

    111
    Density of 3 M NaCl solution is 1.25 g/mL1.25\text{ }g/mL. The molality of the solution is :

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  3. Question 3

    Some Basic Concepts of Chemistry. This type asked 7 times: 2021 Paper 14, 14 Jun 2022, 26 Jun 2022, 27 Jan 2024, 31 Jan 2024, 5 Apr 2024, 8 Apr 2024. This one: 8 Apr 2024 See all 7 of this type

    33
    Combustion of glucose (C6H12O6)\left( C_{6}H_{12}O_{6} \right) produces CO2CO_{2} and water. The amount of oxygen (in gg ) required for the complete combustion of 900 g900\text{ }g of glucose is: [Molar mass of glucose in mol−1=180mol^{- 1}= 180 ]

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  4. Question 4

    The p-Block Elements. This type asked 7 times: 2021 Paper 8, 2021 Paper 11, 2021 Paper 24, 25 Jun 2022, 26 Jun 2022, 28 Jun 2022, 6 Apr 2023. This one: 6 Apr 2023 See all 7 of this type

    46
    Match List I with List II
    List I (Compound)List II (Type of bond)
    (A)N2O4N_{2}O_{4}(I)1 N=O1\text{ }N = O bond
    (B)NO2NO_{2}(II)1 N−O−N1\text{ }N - O - N bond
    (C)N2O5N_{2}O_{5}(III)1 N−N1\text{ }N - N bond
    (D)N2ON_{2}O(IV)1 N=N/N≡N1\text{ }N = N/N \equiv N bond
    Choose the correct answer from the options given below:

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  5. Question 5

    Electrochemistry. This type asked 6 times: 28 Jun 2022, 10 Apr 2023, 11 Apr 2023, 23 Jan 2025, 24 Jan 2025, 8 Apr 2026 S2. This one: 8 Apr 2026 S2 See all 6 of this type

    31
    Given at 298 K:EFe2+/Fe⊖=X298\text{ }K:E_{Fe^{2 +}/Fe}^{\ominus}= X Volt
    EFe3+/Fe⊖=Y Volt E_{Fe^{3 +}/Fe}^{\ominus}= Y\text{~Volt~}
    The EFe3+/Fe2+⊖E_{Fe^{3 +}/Fe^{2 +}}^{\ominus} in Volt at 298 K is given by :

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