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Day 171: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    The d- and f-Block Elements. Asked once: 6 Apr 2024 (same type asked 3 times) See all 3 of this type

    150
    Among VO2+,MnO4−VO_{2}^{+},MnO_{4}^{-}and Cr2O72−Cr_{2}O_{7}^{2 -}, the spin-only magnetic moment value of the species with least oxidising ability is______ BM (Nearest integer). (Given atomic number: V=23,Mn=25,Cr=24V = 23,Mn = 25,Cr = 24)

  2. Question 2

    Biomolecules. Asked once: 6 Apr 2024 (same type asked 3 times) See all 3 of this type

    35
    DNA molecule contains 4 bases whose structures are shown below. One of the structures is not correct, identify the incorrect base structure.

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  3. Question 3

    Chemical Kinetics. Asked once: 4 Apr 2024 (same type asked 3 times) See all 3 of this type

    57
    Consider the following transformation involving first order elementary reaction in each step at constant temperature as shown below.
    A+B⇌ Step 1 Step 3C→ Step 2PA + B\overset{\text{~Step~}3}{\overset{\text{~Step~}1}{\rightleftharpoons}}C\overset{\text{~Step~}2}{\rightarrow}P
    Some details of the above reaction are listed below.
    StepRate constant
    (sec⁡−1)\left( \sec^{- 1} \right)
    		Activation energy (kJ mol−1)\left( {kJ\text{ }mol}^{- 1} \right)
    1
    k1k_{1}
    		300
    2
    k2k_{2}
    		200
    3
    k3k_{3}
    Ea3Ea_{3}
    If the overall rate constant of the transformation (k)(k) is given as k=k1k2k3k =\frac{k_{1}k_{2}}{k_{3}} and the overall activation energy (Ea)\left( E_{a} \right) is 400 kJ mol−1400\text{ }kJ{\text{ }mol}^{- 1}, then the value of Ea3Ea_{3} is _____ kJmol−1kJmol^{- 1} (nearest integer)

  4. Question 4

    Hydrocarbons. Asked once: 1 Feb 2024 (same type asked 3 times) See all 3 of this type

    56
    Total number of deactivating groups in aromatic electrophilic substitution reaction among the following is

  5. Question 5

    Aldehydes, Ketones and Carboxylic Acids. Asked once: 31 Jan 2023 (same type asked 3 times) See all 3 of this type

    36
    Propanal and methanal are treated with (i) dil. NaOHNaOH, (ii) heat, (iii) NaCNNaCN and (iv) H3O+H_{3}O^{+} to give product B, C5H8O3C_{5}H_{8}O_{3}. The correct statement for product BB is: it is

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