PYQ Vault
EbooksTutor

Day 24: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Coordination Compounds. This type asked 5 times: 2021 Paper 18, 31 Jan 2023, 1 Feb 2024, 24 Jan 2025, 29 Jan 2025. This one: 29 Jan 2025 See all 5 of this type

    121
    Consider the following low-spin complexes K3[Co(NO2)6],K4[Fe(CN)6],K3[Fe(CN)6]K_{3}\left\lbrack Co\left( NO_{2} \right)_{6} \right\rbrack,K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack,K_{3}\left\lbrack Fe(CN)_{6} \right\rbrack, Cu2[Fe(CN)6]Cu_{2}\left\lbrack Fe(CN)_{6} \right\rbrack and Zn2[Fe(CN)6]Zn_{2}\left\lbrack Fe(CN)_{6} \right\rbrack. The sum of the spin-only magnetic moment values of complexes having yellow colour is _____\_\_\_\_\_ B.M. (answer is nearest integer)

  2. Question 2

    Chemical Kinetics. This type asked 5 times: 25 Jun 2022, 25 Jul 2022, 26 Jul 2022, 24 Jan 2023, 28 Jan 2025. This one: 28 Jan 2025 See all 5 of this type

    32
    For a given reaction R→P,t1/2R \rightarrow P,t_{1/2} is related to [A]0\lbrack A\rbrack_{0} as given in table :
    [A]0/molL−1\lbrack A\rbrack_{0}/molL^{- 1}t1/2/mint_{1/2}/min
    0.100200
    0.025100
    Given : log2=0.30log2 = 0.30 Which of the following is true? (A) The order of the reaction is 12\frac{1}{2}. (B) If [A]0\lbrack A\rbrack_{0} is 1 M , then t1/2t_{1/2} is 20010 min⁡200\sqrt{10}\text{ }\min (C) The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M . (D) t1/2t_{1/2} is 800 min for [A]0=1.6M\lbrack A\rbrack_{0}= 1.6M Choose the correct answer from the options given below :

    Tap an option to check your answer.

  3. Question 3

    Chemical Thermodynamics. This type asked 5 times: 2021 Paper 21, 2021 Paper 25, 25 Jun 2022, 6 Apr 2024, 24 Jan 2025. This one: 24 Jan 2025 See all 5 of this type

    47
    Standard entropies of X2,Y2X_{2},Y_{2} and XY5XY_{5} are 70,50 and 110 J K−1 mol−1110\text{ }J{\text{ }K}^{- 1}{\text{ }mol}^{- 1} respectively. The temperature in Kelvin at which the reaction
    12X2+52Y2→XY5ΔH⊖=−35 kJ mol−1\frac{1}{2}X_{2}+\frac{5}{2}Y_{2}\rightarrow XY_{5}\quad \Delta H^{\ominus}= - 35\text{ }kJ{\text{ }mol}^{- 1}
    will be at equilibrium is _______\_\_\_\_\_\_\_ (Nearest integer)

  4. Question 4

    Coordination Compounds. This type asked 5 times: 2021 Paper 20, 29 Jun 2022, 8 Apr 2024, 23 Jan 2025, 24 Jan 2025. This one: 24 Jan 2025 See all 5 of this type

    28
    One mole of the octahedral complex compound Co(NH3)5Cl3Co\left( NH_{3} \right)_{5}Cl_{3} gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of AgNO3AgNO_{3} solution to yield two moles of AgCl(s)AgCl_{(s)}. The structure of the complex is :

    Tap an option to check your answer.

  5. Question 5

    The d- and f-Block Elements. This type asked 5 times: 2021 Paper 15, 27 Jun 2022, 28 Jul 2022, 31 Jan 2023, 22 Jan 2025. This one: 22 Jan 2025 See all 5 of this type

    30
    Lanthanoid ions with 4f74f^{7} configuration are: (A) Eu2+Eu^{2 +} (B) Gd3+Gd^{3 +} (C) Eu3+Eu^{3 +} (D) Tb3+Tb^{3 +} (E) Sm2+Sm^{2 +} Choose the correct answer from the options given below :

    Tap an option to check your answer.