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Day 292: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Chemical Kinetics. Asked once: 27 Jun 2022 (same type asked 5 times) See all 5 of this type

    56
    The rate constant for a first order reaction is given by the following equation:
    ln⁡k=33.24−2.0×104 K T\ln k = 33.24 -\frac{2.0 \times10^{4}\text{ }K}{\text{ }T}
    The Activation energy for the reaction is ____\_\_\_\_ kJ mol−1kJ\ mol^{- 1}. (In Nearest integer) (Given: R=8.3 J K−1 mol−1R = 8.3\text{ }J{\text{ }K}^{- 1}{\text{ }mol}^{- 1} )

  2. Question 2

    Organic Chemistry - Some Basic Principles and Techniques. Asked once: 10 Apr 2023 (same type asked 5 times) See all 5 of this type

    31
    Using column chromatography, mixture of two compounds ' AA ' and ' BB ' was separated. ' AA ' eluted first, this indicates ' BB ' has

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  3. Question 3

    The p-Block Elements. Asked once: 7 Apr 2025 (same type asked 5 times) See all 5 of this type

    38
    The group 14 elements A and B have the first ionisation enthalpy values of 708 and 715 kJ mol−1715\text{ }kJ{\text{ }mol}^{- 1} respectively. The above values are lowest among their group members. The nature of their ions A2+A^{2 +} B4+B^{4 +} respectively is.

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  4. Question 4

    Classification of Elements and Periodicity. Asked once: 28 Jun 2022 (same type asked 5 times) See all 5 of this type

    126
    Match List-I with List-II.
    List-I (Oxide)List-II (Nature)
    (A)Cl2O7Cl_{2}O_{7}(I)Amphoteric
    (B)Na2ONa_{2}O(II)Basic
    (C)Al2O3Al_{2}O_{3}(III)Neutral
    (D)N2ON_{2}O(IV)Acidic
    Choose the correct answer from the options given below:

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  5. Question 5

    Electrochemistry. Asked once: 29 Jul 2022 (same type asked 5 times) See all 5 of this type

    51
    Resistance of a conductivity cell (cell constant 129 m−1129{\text{ }m}^{- 1} ) filled with 74.5ppm74.5ppm solution of KClKCl is 100Ω100\Omega (labelled as solution 1). When the same cell is filled with KClKCl solution of 149ppm149ppm, the resistance is 50Ω50\Omega (labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. ∧1∧2=x×10−3\frac{\land_{1}}{\land_{2}}= x \times10^{- 3}. The value of xx is______(Nearest integer) Given, molar mass of KClKCl is 74.5 g mol−174.5\text{ }g{\text{ }mol}^{- 1}