PYQ Vault

Day 307: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Chemical Thermodynamics. Asked once: 27 Jun 2022 (same type asked 4 times) See all 4 of this type

    144
    When 5 moles of He gas expand isothermally and reversibly at 300 K300\text{ }K from 10 litre to 20 litre, the magnitude of the maximum work obtained is ____\_\_\_\_ JJ. [nearest integer] (Given: R=8.3 J K−1 mol−1R = 8.3\text{ }J{\text{ }K}^{- 1}{\text{ }mol}^{- 1} and log⁡2=0.3010)\log2 = 0.3010)
  2. Question 2

    Electrochemistry. Asked once: 10 Apr 2023 (same type asked 4 times) See all 4 of this type

    149
    The specific conductance of 0.0025M0.0025M acetic acid is 5×10−5 S cm−15 \times10^{- 5}\text{ }S{\text{ }cm}^{- 1} at a certain temperature. The dissociation constant of acetic acid is____ 10−710^{- 7}. (Nearest integer) Consider limiting molar conductivity of CH3COOHCH_{3}COOH as 400 S cm2 mol−1400\text{ }S{\text{ }cm}^{2}{\text{ }mol}^{- 1}
  3. Question 3

    Aldehydes, Ketones and Carboxylic Acids. Asked once: 29 Jan 2024 (same type asked 4 times) See all 4 of this type

    59
    From the compounds given below, number of compounds which give positive Fehling's test is ____ . Benzaldehyde, Acetaldehyde, Acetone, Acetophenone, Methanal, 4-nitrobenzaldehyde, cyclohexane carbaldehyde.
  4. Question 4

    Coordination Compounds. Asked once: 2021 Paper 4 (same type asked 4 times) See all 4 of this type

    31
    Given below are two statements: Statement I: The identification of Ni2+Ni^{2 +} is carried out by dimethyl glyoxime in the presence of NH4OHNH_{4}OH Statement II: The dimethyl glyoxime is a bidentate neutral ligand. In the light of the above statements, choose the correct answer from the options given below:

    Tap an option to check your answer.

  5. Question 5

    Hydrocarbons. Asked once: 31 Jan 2023 (same type asked 4 times) See all 4 of this type

    35
    Choose the correct set of reagents for the following conversion. trans (Ph−CH=CH−CH3)→cis(Ph−CH=CH−CH3)\left( Ph - CH = CH -CH_{3} \right)\rightarrow cis\left( Ph - CH = CH -CH_{3} \right)

    Tap an option to check your answer.