PYQ Vault

Day 461: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Haloalkanes and Haloarenes. Asked once: 9 Apr 2024

    39
    Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R) Assertion (A): SN2S_{N}2 reaction of C6H5CH2BrC_{6}H_{5}CH_{2}Br occurs more readily than the SN2S_{N}2 reaction of CH3CH2BrCH_{3}CH_{2}Br. Reason (R): The partially bonded unhybridized p-orbital that develops in the trigonal bipyramidal transition state is stabilized by conjugation with the phenyl ring. In the light of the above statements, choose the most appropriate answer from the options given below:

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  2. Question 2

    Hydrocarbons. Asked once: 2 Apr 2025

    27
    An optically active alkyl halide C4H9Br[A]C_{4}H_{9}Br\lbrack A\rbrack reacts with hot KOH dissolved in ethanol and forms alkene [B] as major product which reacts with bromine to give dibromide [C]. The compound [C] is converted into a gas [D] upon reacting with alcoholic NaNH2NaNH_{2}. During hydration 18 gram of water is added to 1 mole of gas [D] on warming with mercuric sulphate and dilute acid at 333 K to form compound [E]. The IUPAC name of compound [E] is :

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  3. Question 3

    Organic Chemistry - Some Basic Principles and Techniques. Asked once: 28 Jan 2025

    106
    The purification method based on the following physical transformation is :  solid (X)→Heat Vapour (X)→Cool\underset{(X)}{\text{~solid~}}\overset{Heat}{\rightarrow}\underset{(X)}{\text{~Vapour~}}\overset{Cool}{\rightarrow} (X)

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  4. Question 4

    Organic Reaction Mechanisms. Asked once: 8 Apr 2023

    132
    Major product ' PP ' formed in the following reaction is:

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  5. Question 5

    Solutions. Asked once: 1 Feb 2024

    145
    Mass of ethylene glycol (antifreeze) to be added to 18.6 kg18.6\text{ }kg of water to protect the freezing point at −24∘C-24^{\circ}C is ____________ kgkg (Molar mass in gmol−1gmol^{- 1} for ethylene glycol 62, Kf62,{\text{ }K}_{f} of water =1.86 K kg mol−1= 1.86\text{ }K\text{ }kg{\text{ }mol}^{- 1} )