PYQ Vault

Day 61: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Coordination Compounds. This type asked 3 times: 22 Jan 2025, 24 Jan 2025, 2 Apr 2025. This one: 2 Apr 2025 See all 3 of this type

    40
    Given below are two statements : Statement (I) : In octahedral complexes, when Δo<P\Delta_{o} < P high spin complexes are formed. When Δ0>P\Delta_{0} > P low spin complexes are formed. Statement (II) : In tetrahedral complexes because of Δt<P\Delta_{t} < P, low spin complexes are rarely formed. In the light of the above statements, choose the most appropriate answer from the options given below :

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  2. Question 2

    Some Basic Concepts of Chemistry. This type asked 3 times: 27 Jun 2022, 27 Jan 2024, 2 Apr 2025. This one: 2 Apr 2025 See all 3 of this type

    112
    ' x ' g of NaCl is added to water in a beaker with a lid. The temperature of the system is raised from 1∘C1^{\circ}C to 25∘C25^{\circ}C. Which out of the following plots, is best suited for the change in the molarity (M) of the solution with respect to temperature ?[Consider the solubility of NaCl remains unchanged over the temperature range]

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  3. Question 3

    Some Basic Concepts of Chemistry. This type asked 3 times: 2021 Paper 3, 14 Jun 2022, 2 Apr 2025. This one: 2 Apr 2025 See all 3 of this type

    42
    On complete combustion 1.0 g of an organic compound ( X ) gave 1.46 g of CO2CO_{2} and 0.567 g of H2OH_{2}O. The empirical formula mass of compound (X) is ___ g .(Given molar mass in gmol−1C:12,H:1,O:16gmol^{- 1}C:12,H:1,O:16 )

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  4. Question 4

    Amines. This type asked 3 times: 2021 Paper 2, 30 Jan 2024, 29 Jan 2025. This one: 29 Jan 2025 See all 3 of this type

    116
    Which one of the following reaction sequences will give an azo dye?

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  5. Question 5

    Chemical Thermodynamics. This type asked 3 times: 10 Apr 2023, 24 Jan 2025, 29 Jan 2025. This one: 29 Jan 2025 See all 3 of this type

    114
    If C (diamond) →C\rightarrow C (graphite) +XkJmol−1+ XkJmol^{- 1}
    C( diamond )+O2( g)→CO2( g)+Y kJ mol−1C( graphite )+O2( g)→CO2( g)+Z kJ mol−1\begin{matrix} & C(\text{~diamond~}) +O_{2}(\text{ }g) \rightarrow CO_{2}(\text{ }g) + Y\text{ }kJ{\text{ }mol}^{- 1} \\ & C(\text{~graphite~}) +O_{2}(\text{ }g) \rightarrow CO_{2}(\text{ }g) + Z\text{ }kJ{\text{ }mol}^{- 1} \end{matrix}
    At constant temperature. Then

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