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Convert between crystal field splitting energy and the wavelength absorbed

This type of question, asked 2 times: 25 Jun 2022, 31 Jan 2023. All 2 questions below, oldest first.

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  1. Question 1

    25 Jun 2022

    59
    If [Cu(H2O)4]2+\left\lbrack Cu\left( H_{2}O \right)_{4} \right\rbrack^{2 +} absorbs a light of wavelength 600 nmnm for d−dd - d transition, then the value of octahedral crystal field splitting energy for [Cu(H2O)6]2+\left\lbrack Cu\left( H_{2}O \right)_{6} \right\rbrack^{2 +} will be ____ ×10−21 J\times10^{- 21}\text{ }J. (Nearest Integer) (Given: h=6.63×10−34 J sh = 6.63 \times10^{- 34}\text{ }J\text{ }s and c=3.08×108 ms−1c = 3.08 \times10^{8}{\text{ }ms}^{- 1})

  2. Question 2

    31 Jan 2023

    146
    If the CFSE of [Ti(H2O)6]3+\left\lbrack Ti\left( H_{2}O \right)_{6} \right\rbrack^{3 +} is −96.0 kJ mol−1-96.0\text{ }kJ\text{ }mol^{- 1}, this complex will absorb maximum at wavelength ____ nmnm. (nearest integer) Assume Planck's constant ( h)=6.4×10−34Jsh) = 6.4 \times10^{- 34}Js, Speed of light (c) =3.0×108 m s−1= 3.0 \times10^{8}\text{ }m\text{ }s^{- 1} and Avogadro's Constant (NA)=6×1023 mol−1\left( N_{A} \right)= 6 \times10^{23}\text{ }mol^{- 1}