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Products of electrolysis of aqueous solutions

This type of question, asked 3 times: 31 Jan 2023, 29 Jan 2025, 7 Apr 2025. All 3 questions below, oldest first.

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  1. Question 1

    31 Jan 2023

    49
    Which one of the following statements is correct for electrolysis of brine solution?

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  2. Question 2

    29 Jan 2025

    111
    O2O_{2} gas will be evolved as a product of electrolysis of : (a) an aqueous solution of AgNO3AgNO_{3} using silver electrodes. (b) an aqueous solution of AgNO3AgNO_{3} using platinum electrodes. (c) a dilute solution of H2SO4H_{2}SO_{4} using platinum electrodes. (d) a high concentration solution of H2SO4H_{2}SO_{4} using platinum electrodes. Choose the correct answer from the options given below :

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  3. Question 3

    7 Apr 2025

    119
    Given below are two statements : 1 M aqueous solution of each of Cu(NO3)2Cu\left( NO_{3} \right)_{2}, AgNO3,Hg2(NO3)2;Mg(NO3)2AgNO_{3},Hg_{2}\left( NO_{3} \right)_{2};Mg\left( NO_{3} \right)_{2} are electrolysed using inert electrodes, Given : EAg+/Agθ=0.80 V,EHg22+/Hgθ=0.79 VE_{{Ag}^{+}/Ag}^{\theta} = 0.80\text{ }V,E_{{Hg}_{2}^{2 +}/Hg}^{\theta} = 0.79\text{ }V,
    ECu2+/Cuθ=0.24 V and EMg2+/Mgθ=−2.37 VE_{{Cu}^{2 +}/Cu}^{\theta} = 0.24\text{ }V\text{~and~}E_{{Mg}^{2 +}/Mg}^{\theta} = - 2.37\text{ }V
    Statement (I) : With increasing voltage, the sequence of deposition of metals on the cathode will be Ag,HgAg,Hg and Cu Statement (II) : Magnesium will not be deposited at cathode instead oxygen gas will be evolved at the cathode. In the light of the above statement, choose the most appropriate answer from the options given below

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