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Limiting molar conductivity of an electrolyte from those of others (Kohlrausch's law)

This type of question, asked 3 times: 27 Jun 2022, 5 Apr 2024, 7 Apr 2025. All 3 questions below, oldest first.

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  1. Question 1

    27 Jun 2022

    55
    The limiting molar conductivities of NaI,NaNO3NaI,NaNO_{3} and AgNO3AgNO_{3} are 12.7, 12.0 and 13.3 mS m2 mol−113.3\ mS\ m^{2}\ mol^{-1}, respectively (all at 25∘C25^{\circ}C ). The limiting molar conductivity of AgI at this temperature is ____ mS m2 mol−1\_\_\_\_\ mS\ m^{2}\ mol^{-1}
  2. Question 2

    5 Apr 2024

    49
    Molar ionic conductivities of divalent cation and anion are 57 S cm2 mol−157\text{ }S{\text{ }cm}^{2}{\text{ }mol}^{- 1} and 73 S cm2 mol−173\text{ }S{\text{ }cm}^{2}{\text{ }mol}^{- 1} respectively. The molar conductivity of solution of an electrolyte with the above cation and anion will be :

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  3. Question 3

    7 Apr 2025

    35
    Given below are two statements: Statement I : Mohr's salt is composed of only three types of ions-ferrous, ammonium and sulphate. Statement II : If the molar conductance at infinite dilution of ferrous, ammonium and sulphate ions are x1,x2x_{1},x_{2} and x3 S cm2 mol−1x_{3}\text{ }S{\text{ }cm}^{2}{\text{ }mol}^{- 1}, respectively then the molar conductance for Mohr's salt solution at infinite dilution would be given by x1+x2+2x3x_{1} + x_{2} + 2x_{3} In the light of the given statements, choose the correct answer from the options given below

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