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Number of electrons or ion charge from a measured EMF and reaction quotient

This type of question, asked 2 times: 25 Jul 2022, 4 Apr 2026 S2. All 2 questions below, oldest first.

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  1. Question 1

    25 Jul 2022

    54
    The cell potential for Zn∣Zn2+(aq)∣∣Snx+∣SnZn\left| Zn^{2+}(aq) \right|\left| Sn^{x+} \right|Sn is 0.801 V0.801\text{ }V at 298 K298\text{ }K. The reaction quotient for the above reaction is 10−210^{-2}. The number of electrons involved in the given electrochemical cell reaction is ____. (Given EZn2+∣Zn0=−0.763 V,ESnx+∣Sn0=+0.008 VE_{Zn^{2+}\mid Zn}^{0}= -0.763\text{ }V, E_{Sn^{x+}\mid Sn}^{0}= +0.008\text{ }V and 2.303RTF=0.06 V\frac{2.303RT}{F}= 0.06\text{ }V)

  2. Question 2

    4 Apr 2026 S2

    48
    An electrochemical cell. consist of the following two redox couples, Mx+(aq)/M(s)[Ered ⊖=+0.15 V]M^{x +}(aq)/M(s)\left\lbrack E_{\text{red~}}^{\ominus} = + 0.15\text{ }V \right\rbrack and Fe3+(aq)/Fe(s)[Ered ⊖=−0.036 V]{Fe}^{3 +}(aq)/Fe(s)\left\lbrack E_{\text{red~}}^{\ominus} = - 0.036\text{ }V \right\rbrackThe cell EMF ( Ecell E_{\text{cell~}} ) is recorded to be 0.2057 V . If the reaction quotient of the electrochemical reaction is found to be 10−210^{- 2}, then the value of x is ____\_\_\_\_ (Nearest integer) [Given : M is a p-block metal and  2.303RTF=0.059 V]\left. \ \frac{2.303RT}{F} = 0.059\text{ }V \right\rbrack