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Molar solubility from the Ksp of a given salt

This type of question, asked 4 times: 2021 Paper 4, 25 Jun 2022, 29 Jul 2022, 24 Jan 2025. All 4 questions below, oldest first.

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  1. Question 1

    2021 Paper 4

    50
    The solubility of Ca(OH)2Ca(OH)_{2} in water is: [Given : The solubility product of Ca(OH)2Ca(OH)_{2} in water =5.5×10−6= 5.5 \times10^{- 6} ]

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  2. Question 2

    25 Jun 2022

    124
    The KspK_{sp} for bismuth sulphide (Bi2 S3)\left( Bi_{2}{\text{ }S}_{3} \right) is 1.08×10−731.08 \times10^{- 73}. The solubility of Bi2 S3Bi_{2}{\text{ }S}_{3} in molL−1molL^{- 1} at 298 K298\text{ }K is

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  3. Question 3

    29 Jul 2022

    56
    If the solubility product of PbSPbS is 8×10−288 \times10^{- 28}, then the solubility of PbSPbS in pure water at 298 K298\text{ }K is x×10−16 mol L−1x \times10^{- 16}\text{ }mol{\text{ }L}^{- 1}. The value of xx is ____(Nearest Integer) [Given 2=1.41\sqrt{2}= 1.41 ]
  4. Question 4

    24 Jan 2025

    32
    Ksp for Cr(OH)3Cr(OH)_{3} is 1.6×10−301.6 \times10^{- 30}. What is the molar solubility of this salt in water?

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