Alkylation of a terminal alkyne with NaNH2 and an alkyl halide

1. A.
   $A = {CH}_{3} - C \equiv C^{-}Na^{+},\text{ }B = {CH}_{3} - {CH}_{2} - {CH}_{2} - Br$
2. B.
   $A = {CH}_{3} - CH = {CH}_{2},\text{ }B = {CH}_{3} - {CH}_{2} - {CH}_{2} - Br$
3. C.
   $A = {CH}_{3} - {CH}_{2} - {CH}_{3},\text{ }B = {CH}_{3} - C \equiv CH$
4. D.
   $A = {CH}_{3} - C \equiv C^{-}Na^{+},\text{ }B = {CH}_{3} - {CH}_{2} - {CH}_{3}$

Tap an option to check your answer.

1. A.
   2-methylhex-2-yne
2. B.
   5-methylhex-2-yne
3. C.
   2-methylhex-3-yne
4. D.
   Isopropylbut-1-yne

Tap an option to check your answer.