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Carius method: an organic compound gives AgBr in the ratio 0.2 g to 0.188 g: percentage of bromine

The same question, asked 2 times: 2021 Paper 20*, 13 Apr 2023. Every wording below, oldest first.

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  1. Question 1

    2021 Paper 20

    51
    In Carius method for estimation of halogens, 0.2 g0.2\text{ }g of an organic compound gave 0.188 g0.188\text{ }g of AgBrAgBr. The percentage of bromine in the compound is . (Nearest integer) [Atomic mass: Ag=108,Br=80Ag = 108,Br = 80 ]

  2. Question 2

    13 Apr 2023

    141
     0.400 g\ 0.400\text{ }g of an organic compound (X) gave 0.376 g0.376\text{ }g of AgBrAgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is____ (Given: Molar mass AgBr=188 g mol−1Br=80 gAgBr = 188\text{ }g{\text{ }mol}^{- 1}Br = 80\text{ }g mol−1mol^{- 1} )