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Percentage of sulphur from the mass of barium sulphate (Carius method)

This type of question, asked 8 times: 2021 Paper 19, 25 Jan 2023, 23 Jan 2025, 29 Jan 2025, 21 Jan 2026 S1, 28 Jan 2026 S2, 4 Apr 2026 S2, 5 Apr 2026 S1. All 8 questions below, oldest first.

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  1. Question 1

    2021 Paper 19

    51
    In the sulphur estimation, 0.471 g0.471\text{ }g of an organic compound gave 1.44 g1.44\text{ }g of barium sulphate. The percentage of sulphur in the compound is %\%. (Nearest integer) (Atomic Mass of Ba=137uBa = 137u )

  2. Question 2

    25 Jan 2023

    53
    In sulphur estimation, 0.471 g0.471\text{ }g of an organic compound gave 1.4439 g1.4439\text{ }g of barium sulphate. The percentage of sulphur in the compound is _____(Nearest Integer) (Given: Atomic mass Ba: 137u, S: 32u, 0:16u )

  3. Question 3

    23 Jan 2025

    47
    During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is____\_\_\_\_ %.(Given molar mass in gmol−1gmol^{- 1} of Ba:137, S:32Ba:137,\text{ }S:32, 0:16)0:16)

  4. Question 4

    29 Jan 2025

    124
    In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is _____\_\_\_\_\_ ×10−1\times10^{- 1} %\%. (Molar mass : O=16, S=32,Ba=137ingmol −1O = 16,\text{ }S = 32,Ba = 137in_{gmol}\ ^{- 1} )

  5. Question 5

    21 Jan 2026 S1

    33
    In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol−132\text{ }g{\text{ }mol}^{- 1}). Molar mass of barium sulphate is 233 g mol−1233\text{ }g{\text{ }mol}^{- 1}.

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  6. Question 6

    28 Jan 2026 S2

    45
    A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of Sulphur present in the compound is ____\_\_\_\_ . (Given Molar mass in gmol−1 S:32,BaSO4:233gmol^{- 1}\text{ }S:32,BaSO_{4}:233 )

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  7. Question 7

    4 Apr 2026 S2

    50
    In Sulphur estimation, 2.0×10−3 mol2.0 \times 10^{- 3}\text{ }mol of an organic compound (X) (molar mass 76 g mol−176\text{ }g{\text{ }mol}^{- 1} ) gave 0.4813 g of barium sulphate (molar mass 233gmol−1233{gmol}^{- 1} ). The percentage of sulphur in the compound ( X ) is ____\_\_\_\_ ×10−1%\times 10^{- 1}\% (Nearest integer)

  8. Question 8

    5 Apr 2026 S1

    47
    In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of BaSO4{BaSO}_{4}. The percentage of sulphur in the substance is ____\_\_\_\_ %. (Given molar mass in gmol−1 S:32,BaSO4:231g{mol}^{- 1}\text{ }S:32,{BaSO}_{4}:231 )