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Freezing or boiling point of a solution from the masses of a non-electrolyte solute and the solvent

This type of question, asked 4 times: 2021 Paper 19, 2021 Paper 21, 28 Jul 2022, 3 Apr 2025. All 4 questions below, oldest first.

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  1. Question 1

    2021 Paper 19

    58
     83 g\ 83\text{ }g of ethylene glycol dissolved in 625 g625\text{ }g of water. The freezing point of the solution is ____ K. (Nearest integer) [Use: Molal Freezing point depression constant of water  =1.86 K kg mol−1]\left. \ = 1.86\text{ }K\text{ }kg{\text{ }mol}^{- 1} \right\rbrack Freezing Point of water =273 K= 273\text{ }K Atomic masses: C : 12.0u,O:16.0u,H:1.0u]12.0u,O:16.0u,H:1.0u\rbrack

  2. Question 2

    2021 Paper 21

    55
    40 g40\text{ }g of glucose (Molar mass =180)= 180) is mixed with 200 mL200\text{ }mL of water. The freezing point of solution is ____ K. (Nearest integer) [Given: Kf=1.86 K kg mol−1K_{f}= 1.86\text{ }K\text{ }kg{\text{ }mol}^{- 1}; Density of water == 1.00 g cm−3;1.00\text{ }g{\text{ }cm}^{- 3}; Freezing point of water  =273.15 K]\left. \ = 273.15\text{ }K \right\rbrack

  3. Question 3

    28 Jul 2022

    54
    150 g150\text{ }g of acetic acid was contaminated with 10.2 g10.2\text{ }g ascorbic acid (C6H8O6)\left( C_{6}H_{8}O_{6} \right) to lower down its freezing point by (x×10−1)∘C\left( x \times10^{- 1} \right)^{\circ}C. The value of xx is (Nearest integer) [Given Kf=3.9 K kg mol−1K_{f}= 3.9\text{ }K\text{ }kg{\text{ }mol}^{- 1}; Molar mass of ascorbic acid =176 g mol−1= 176\text{ }g{\text{ }mol}^{- 1} ]

  4. Question 4

    3 Apr 2025

    41
    2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is : (Given : Ebullioscopic constant of water =0.52 K kg mol−1= 0.52\text{ }K\text{ }kg{\text{ }mol}^{- 1} )

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