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Osmotic pressure of a solution from the mass of solute and the volume

This type of question, asked 3 times: 26 Jun 2022, 24 Jan 2026 S1, 2 Apr 2026 S2. All 3 questions below, oldest first.

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  1. Question 1

    26 Jun 2022

    145
    The osmotic pressure exerted by a solution prepared by dissolving 2.0 g2.0\text{ }g of protein of molar mass 60 kg mol−160\text{ }kg{\text{ }mol}^{- 1} in 200 mL200\text{ }mL of water at 27∘C27^{\circ}C is ____ PaPa. [integer value] (use R=0.083 Lbarmol−1 K−1R = 0.083\text{ }Lbarmol^{- 1}{\text{ }K}^{- 1} )

  2. Question 2

    24 Jan 2026 S1

    30
    A solution is prepared by dissolving 0.3 g of a nonvolatile non-electrolyte solute ' A ' of molar mass 60 g mol−160\text{ }g{\text{ }mol}^{- 1} and 0.9 g of a non-volatile nonelectrolyte solute ' B ' of molar mass 180 g mol−1180\text{ }g{\text{ }mol}^{- 1} in 100 mLH2O100\text{ }mLH_{2}O at 27∘C27^{\circ}C. Osmotic pressure of the solution will be [Given : R=0.082 L atm K−1 mol−1R = 0.082\text{ }L\text{ }atm{\text{ }K}^{- 1}{\text{ }mol}^{- 1} ]

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  3. Question 3

    2 Apr 2026 S2

    30
    Solution A is prepared by dissolving 1 g of a protein (molar mass =50000 g mol−1= 50000\text{ }g{\text{ }mol}^{- 1} ) in 0.5 L of water at 300 K . Its osmotic pressure is x bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K . Osmotic pressure of solution BB is y bar. Entire solution of AA is mixed with entire solution of BB at same temperature. The osmotic pressure of resultant solution is zz bar. x,yx,y and z respectively are : ( R=0.083 LR = 0.083\text{ }L bar mol−1 K−1mol^{- 1}{\text{ }K}^{- 1} )

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