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Blast furnace Fe3O4 + 4CO: mass of iron from given masses of Fe3O4 and CO

The same question, asked 2 times: 29 Jun 2022*, 24 Jan 2025. Every wording below, oldest first.

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  1. Question 1

    29 Jun 2022

    31
    Production of iron in blast furnace follows the following equation
    Fe3O4( s)+4CO(g)→3Fe(l)+4CO2( g)Fe_{3}O_{4}(\text{ }s) + 4CO(g) \rightarrow 3Fe(l) + 4CO_{2}(\text{ }g)
    when 4.640 kg4.640\text{ }kg of Fe3O4Fe_{3}O_{4} and 2.520 kg2.520\text{ }kg of COCO are allowed to react then the amount of iron (in gg ) produced is: [Given: Molar Atomic mass (gmol−1):Fe=56\left( gmol^{- 1} \right):Fe = 56 Molar Atomic mass (gmol−1):O=16\left( gmol^{- 1} \right):O = 16 Molar Atomic mass (gmol−1):C=12\left( gmol^{- 1} \right):C = 12]

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  2. Question 2

    24 Jan 2025

    50
    Consider the following reaction occurring in the blast furnace.
    Fe3O4( s)+4CO(g)→3Fe(l)+4CO2( g)Fe_{3}O_{4(\text{ }s)}+ 4CO_{(g)}\rightarrow 3Fe_{(l)}+ 4CO_{2(\text{ }g)}
    'xx' kg of iron is produced when 2.32×103 kg2.32 \times10^{3}\text{ }kg Fe3O4Fe_{3}O_{4} and 2.8×102 kgCO2.8 \times10^{2}\text{ }kgCO are brought together in the furnace. The value of ' xx ' is ____\_\_\_\_ . (nearest integer) {Given : Molar mass of Fe3O4=232 g mol−1Fe_{3}O_{4}= 232\text{ }g{\text{ }mol}^{- 1} Molar mass of CO=28 g mol−1CO = 28\text{ }g{\text{ }mol}^{- 1} Molar mass of  Fe=56 g mol−1}\left. \ Fe = 56\text{ }g{\text{ }mol}^{- 1} \right\}