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Molarity after dilution, mixing or evaporation

This type of question, asked 4 times: 25 Jun 2022, 26 Jul 2022, 24 Jan 2023, 22 Jan 2025. All 4 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    25 Jun 2022

    55
    1 L1\text{ }L aqueous solution of H2SO4H_{2}SO_{4} contains 0.02 m mol0.02\text{ }m\text{ }mol of H2SO4H_{2}SO_{4}. 50%50\% of this solution is diluted with deionized water to give 1 L1\text{ }L solution (a). In solution (a), 0.01 m mol0.01\text{ }m\text{ }mol of H2SO4H_{2}SO_{4} are added. Total mm mols of H2SO4H_{2}SO_{4} in the final solution is ____ ×10−3 m mol\times10^{- 3}\text{ }m\text{ }mol.

  2. Question 2

    26 Jul 2022

    55
    When 800 mL800\text{ }mL of 0.5M0.5M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g11.5\text{ }g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x×10−2Mx \times10^{- 2}M. (Nearest Integer) (Molar mass of nitric acid is 63 g mol−163\text{ }g{\text{ }mol}^{- 1} )

  3. Question 3

    24 Jan 2023

    54
     5 g\ 5\text{ }g of NaOHNaOH was dissolved in deionized water to prepare a 450 mL450\text{ }mL stock solution. What volume (in mLmL ) of this solution would be required to prepare 500 mL500\text{ }mL of 0.1M0.1M solution? Given: Molar Mass of Na,ONa,O and HH is 23,16 and 1 g mol−11\text{ }g{\text{ }mol}^{- 1} respectively

  4. Question 4

    22 Jan 2025

    125
    20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _______\_\_\_\_\_\_\_ ×10−2M\times10^{- 2}M. (Nearest integer).