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de Broglie wavelength from mass and velocity or kinetic energy

This type of question, asked 3 times: 26 Jul 2022, 6 Apr 2023, 28 Jan 2026 S2. All 3 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    26 Jul 2022

    53
    The wavelength of an electron and a neutron will become equal when the velocity of the electron is xx times the velocity of neutron. The value of xx is. (Nearest Integer) (Mass of electron is 9.1×10−31 kg9.1 \times10^{- 31}\text{ }kg and mass of neutron is 1.6×10−27 kg1.6 \times10^{- 27}\text{ }kg )

  2. Question 2

    6 Apr 2023

    51
    The wavelength of an electron of kinetic energy 4.50×10−29 J4.50 \times10^{- 29}\text{ }J is...... ×10−5 m\times10^{- 5}\text{ }m. (Nearest integer) Given: mass of electron is 9×10−31 kg, h=6.6×9 \times10^{- 31}\text{ }kg,\text{ }h = 6.6 \times 10−34 J S10^{- 34}\text{ }J\text{ }S

  3. Question 3

    28 Jan 2026 S2

    46
    Two positively charged particles m1m_{1} and m2m_{2} have been accelerated across the same potential difference of 200 keV as shown below. [Given mass of m1=1amum_{1} = 1amu and m2=4amum_{2} = 4amu ] The DE Broglie wavelength of m1m_{1} will be x times of m2m_{2}. The value of x is ____\_\_\_\_ (nearest integer)