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Rydberg formula: compare the wavelengths or energies of two spectral lines (H or He+)

This type of question, asked 8 times: 24 Jan 2023, 29 Jan 2023, 31 Jan 2023, 21 Jan 2026 S2, 22 Jan 2026 S2, 24 Jan 2026 S1, 4 Apr 2026 S1, 6 Apr 2026 S1. All 8 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    24 Jan 2023

    55
    If wavelength of the first line of the Paschen series of hydrogen atom is 20 nm20\text{ }nm, then the wavelength of the second line of this series is ____ nmnm. (Nearest integer)
  2. Question 2

    29 Jan 2023

    34
    The shortest wavelength of hydrogen atom in Lyman series is λ\lambda. The longest wavelength in Balmer series of He+He^{+}is

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  3. Question 3

    31 Jan 2023

    50
    Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from n=4n = 4 to n=2n = 2 of He+He^{+}spectrum

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  4. Question 4

    21 Jan 2026 S2

    26
    Consider the following spectral lines for atomic hydrogen: (A) First line of Paschen series (B) Second line of Balmer series (C) Third line of Paschen series (D) Fourth line of Brackett series The correct arrangement of the above lines in ascending order of energy is:

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  5. Question 5

    22 Jan 2026 S2

    39
    The energy of first (lowest) Balmer line of H atom is x J . The energy (in J) of second Balmer line of H atom is :

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  6. Question 6

    24 Jan 2026 S1

    48
    The hydrogen spectrum consists of several spectral lines in Lyman series (L1, L2, L3….;L1\left( L_{1},{\text{ }L}_{2},{\text{ }L}_{3}\ldots.;L_{1} \right. has lowest energy among Lyman series). Similarly it consists of several spectral lines in Balmer series ( B1, B2B_{1},{\text{ }B}_{2}, B3…….;B1B_{3}\ldots\ldots.;B_{1} has lowest energy among Balmer lines). The energy of L1L_{1} is x times the energy of B1B_{1}. The value of xx is ____\_\_\_\_ ×10−1\times 10^{- 1} (Nearest integer)
  7. Question 7

    4 Apr 2026 S1

    27
    What is the ratio of wave number of first line (lowest energy line) of Balmer series of H atomic spectrum to first line of its Brackett series?

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  8. Question 8

    6 Apr 2026 S1

    27
    If shortest wavelength of hydrogen atom in Lyman series is x , then longest wavelength in Balmer series of He+He^{+}is :

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