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Order of orbital energies in a multielectron atom from quantum numbers (n + l rule)

This type of question, asked 5 times: 27 Jul 2022, 29 Jul 2022, 31 Jan 2023, 9 Apr 2024, 5 Apr 2026 S1. All 5 questions below, oldest first.

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  1. Question 1

    27 Jul 2022

    121
    The correct decreasing order of energy, for the orbitals having, following set of quantum numbers: (A) n=3,l=0, m=0n = 3,l = 0,\text{ }m = 0 (B) n=4,l=0, m=0n = 4,l = 0,\text{ }m = 0 (C) n=3,l=1, m=0n = 3,l = 1,\text{ }m = 0 (D) n=3,l=2, m=1n = 3,l = 2,\text{ }m = 1

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  2. Question 2

    29 Jul 2022

    122
    Given below are the quantum numbers for 4 electrons. A. n=3,l=2,ml=1,ms=+1/2n = 3,l = 2,m_{l}= 1,m_{s}= + 1/2 B. n=4,l=1,ml=0,ms=+1/2n = 4,l = 1,m_{l}= 0,m_{s}= + 1/2 C. n=4,l=2,ml=−2,ms=−1/2n = 4,l = 2,m_{l}= - 2,m_{s}= - 1/2 D. n=3,l=1,ml=−1,ms=+1/2n = 3,l = 1,m_{l}= - 1,m_{s}= + 1/2 The correct order of increasing energy is:

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  3. Question 3

    31 Jan 2023

    128
    Arrange the following orbitals in decreasing order of energy. A. n=3,l=0, m=0n = 3,l = 0,\text{ }m = 0 B. n=4,l=0, m=0n = 4,l = 0,\text{ }m = 0 C. n=3,l=1, m=0n = 3,l = 1,\text{ }m = 0 D. n=3,l=2,m=1n = 3,l = 2,m = 1 The correct option for the order is:

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  4. Question 4

    9 Apr 2024

    45
    Compare the energies of following sets of quantum numbers for multielectron system. (A) n=4,l=1n = 4,l = 1 (B) n=4,l=2n = 4,l = 2 (C) n=3,l=1n = 3,l = 1 (D) n=3,l=2n = 3,l = 2 (E) n=4,l=0n = 4,l = 0 Choose the correct answer from the options given below:

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  5. Question 5

    5 Apr 2026 S1

    27
    Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. (A) n=3,l=2, m=+1n = 3,\mathcal{l} = 2,\text{ }m = + 1 (B) n=4,l=0,m=0n = 4,\mathcal{l} = 0,m = 0 (C) n=6,l=1, m=0n = 6,\mathcal{l} = 1,\text{ }m = 0 (D) n=5,l=1, m=+1n = 5,\mathcal{l} = 1,\text{ }m = + 1 (E) n=2,l=1, m=+1n = 2,\mathcal{l} = 1,\text{ }m = + 1 Choose the correct answer from the options given below :

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