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Aniline does not undergo Friedel-Crafts reaction (salt with AlCl3)

This type of question, asked 5 times: 2021 Paper 13, 29 Jun 2022, 26 Jul 2022, 31 Jan 2024, 1 Feb 2024. All 5 questions below, oldest first.

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  1. Question 1

    2021 Paper 13

    39
    Which compound does not give Friedel craft reaction?

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  2. Question 2

    29 Jun 2022

    136
    In Friedel-Crafts alkylation of aniline, one gets:

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  3. Question 3

    26 Jul 2022

    50
    Given below are two statements: one is labelled as Assertion (a) and the other is labelled as Reason (R). Assertion (a): Experimental reaction of CH3ClCH_{3}Cl with aniline and anhydrous AlCl3AlCl_{3} does not give o and p-methylaniline. Reason (R): The −NH2-NH_{2} group of aniline becomes deactivating because of salt formation with anhydrous AlCl3AlCl_{3} and hence yields mm-methyl aniline as the product. In the light of the above statements, choose the most appropriate answer from the options given below:

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  4. Question 4

    31 Jan 2024

    130
    Given below are two statements: Statement I: Aniline reacts with con. H2SO4H_{2}SO_{4} followed by heating at 453−473 K453 - 473\text{ }K gives pp-aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'. Statement II: In Friedel - Craft's alkylation and acylation reactions, aniline forms salt with the AlCl3AlCl_{3} catalyst. Due to this, nitrogen of aniline acquires a positive charge and acts as deactivating group. In the light of the above statements, choose the correct answer from the options given below:

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  5. Question 5

    1 Feb 2024

    50
    Given below are two statements: Statement (I): The NH2NH_{2} group in Aniline is ortho and para directing and a powerful activating group. Statement (II): Aniline does not undergo Friedel- Craft's reaction (alkylation and acylation). In the light of the above statements, choose the most appropriate answer from the options given below:

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