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Borax bead test: compound formed and colour of the bead

This type of question, asked 5 times: 2021 Paper 1, 29 Jul 2022, 29 Jan 2023, 31 Jan 2023, 28 Jan 2026 S2. All 5 questions below, oldest first.

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  1. Question 1

    2021 Paper 1

    48
    Given below are two statements: Statement I : Colourless cupric metaborate is reduced to cuprous metaborate in a luminous flame. Statement II : Cuprous metaborate is obtained by heating boric anhydride and copper sulphate in a non-luminous flame. In the light of the above statements, choose the most appropriate answer from the options given below.

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  2. Question 2

    29 Jul 2022

    129
    When borax is heated with CoOCoO on a platinum loop, blue coloured bead formed is largely due to :

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  3. Question 3

    29 Jan 2023

    39
    During the borax bead test with CuSO4CuSO_{4}, a blue green colour of the bead was observed in oxidising flame due to the formation of

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  4. Question 4

    31 Jan 2023

    130
    Given below are two statements: Statement I: Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green Statement II: The green colour observerd is due to the formation of copper(I) metaborate In the light of the above statements, choose the most appropriate answer from the options given below:

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  5. Question 5

    28 Jan 2026 S2

    42
    Consider the following reactions. Na2B4O7→Δ2X+Y\mathrm{Na_2B_4O_7 \xrightarrow{\Delta} 2X + Y} CuSO4+Y→non-luminous flameZ+SO3\mathrm{CuSO_4 + Y \xrightarrow{\text{non-luminous flame}} Z + SO_3} 2Z+2X+C→luminous flame2Q+Na2B4O7+CO\mathrm{2Z + 2X + C \xrightarrow{\text{luminous flame}} 2Q + Na_2B_4O_7 + CO} The oxidation states of Cu in Z and Q, respectively are:

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