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Product of Hofmann bromamide degradation of a given amide

This type of question, asked 4 times: 2021 Paper 7, 29 Jan 2023, 21 Jan 2026 S1, 5 Apr 2026 S2. All 4 questions below, oldest first.

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  1. Question 1

    2021 Paper 7

    41
    Hoffmann bromomide degradation of benzamide gives product AA, which upon heating with CHCl3CHCl_{3} and NaOHNaOH gives product BB. The structures of AA and BB are:

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  2. Question 2

    29 Jan 2023

    123
    Reaction of propanamide with Br2/KOH(aq)Br_{2}/KOH(aq) produces:

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  3. Question 3

    21 Jan 2026 S1

    35
    An organic compound (P)(P) on treatment with aqueous ammonia under hot condition forms compound (Q)(Q) which on heating with Br2Br_{2} and KOH forms compound (R) having molecular formula C6H7NC_{6}H_{7}N. Names of P,QP,Q and R respectively are.

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  4. Question 4

    5 Apr 2026 S2

    42
    Given below are two statements : Statement-I : Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine. Statement-II : Nitration of aniline with HNO3/H2SO4{HNO}_{3}/H_{2}{SO}_{4} at 288 K produces mm-nitroaniline in higher amount than oo-nitroaniline ( pH adjusted). In the light of the above statements, choose the correct answer from the options given below:

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