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Day 142: JEE Mains Maths

5 questions. Try each one first, then open its answer.

  1. Question 1

    Differentiation. Asked once: 4 Apr 2025 (same type asked 6 times) See all 6 of this type

    75
    Let mm and nn be the number of points at which the function f(x)=f(x) = max⁡{x,x3,x5,……,x21},x∈R\max\left\{ x,x^{3},x^{5},\ldots\ldots,x^{21} \right\},x \in \mathbb{R}, is not differentiable and not continuous, respectively. Then m+nm + n is equal to:

  2. Question 2

    Application of Derivatives. Asked once: 7 Apr 2025 (same type asked 6 times) See all 6 of this type

    133
    Let f:R→Rf:R \rightarrow R be a polynomial function of degree four having extreme values at x=4x = 4 and x=5x = 5.If lim⁡x→0f(x)x2=5\lim_{x \rightarrow 0} \frac{f(x)}{x^{2}}= 5, then f(2)f(2) is equal to :

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  3. Question 3

    Statistics. Asked once: 30 Jan 2023 (same type asked 6 times) See all 6 of this type

    88
    The mean and variance of 7 observations are 8 and 16 respectively. If one observation 14 is omitted and aa and bb are respectively mean and variance of remaining 6 observation, then a+3b−5a + 3b - 5 is equal to

  4. Question 4

    Inverse Trigonometric Functions. Asked once: 28 Jan 2025 (same type asked 6 times) See all 6 of this type

    60
    cos⁡(sin⁡−135+sin⁡−1513+sin⁡−13365)\cos\left( \sin^{- 1}\frac{3}{5}+\sin^{- 1}\frac{5}{13}+\sin^{- 1}\frac{33}{65} \right) is equal to :

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  5. Question 5

    Complex Numbers. Asked once: 24 Jan 2026 S1 (same type asked 6 times) See all 6 of this type

    59
    Let S={z∈C:∣z−6iz−2i∣=1S =\left\{ z\in C:\left| \frac{z - 6i}{z - 2i} \right|= 1 \right. and  ∣z−8+2iz+2i∣=35}\left. \ \left| \frac{z - 8 + 2i}{z + 2i} \right|=\frac{3}{5} \right\}. Then ∑z∈s∣z∣2\sum_{z \in s} |z|^{2} is equal to

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