Integral of |trigonometric expression| by splitting at its zeros
This type of question, asked 3 times: 2021 Paper 25, 29 Jan 2024, 21 Jan 2026 S1. All 3 questions below, oldest first.
Try each one first, then open its answer.
Question 1
2021 Paper 25
90The value of the integral ∫0π∣sin2x∣dx is Question 2
29 Jan 2024
174If ∫6π3π1−sin2xdx=α+β2+γ3, where α,β and γ are rational numbers, then 3α+4β−γ is equal to Question 3
21 Jan 2026 S1
756∫0π∣(sin3x+sin2x+sinx)∣dx is equal to