x log x dy/dx + y = f(x) log x: find y at a point
The same question, asked 2 times: 29 Jan 2023*, 6 Apr 2024. Every wording below, oldest first.
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Question 1
29 Jan 2023
165Let y=y(x) be the solution of the differential equation xlogexdxdy+y=x2logex,(x>1). If y(2)=2, then y(e) is equal to
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Question 2
6 Apr 2024
78Let y=y(x) be the solution of the differential equation (2xlogex)dxdy+2y=x3logex,x>0 and y(e−1)=0. Then, y(e) is equal to
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