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Piecewise function with an integral piece: continuity and differentiability

This type of question, asked 2 times: 2021 Paper 15, 27 Jul 2022. All 2 questions below, oldest first.

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  1. Question 1

    2021 Paper 15

    46
    If f(x)={5x+1,x<2∫0x(5+∣1−t∣) dt,x≥2f(x)=\begin{cases} 5x+1, & x<2 \\ \int_{0}^{x} (5+|1-t|)\,dt, & x\ge 2 \end{cases} then

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  2. Question 2

    27 Jul 2022

    80
    Let a function f:R→Rf:R \rightarrow R be defined as:
    f(x)={∫0x(5−∣t−3∣)dt,x>4x2+bx ,x≤4f(x) =\left\{ \begin{matrix} \int_{0}^{x} (5 - |t - 3|)dt, & x > 4 \\ x^{2}+ bx\ , & x \leq 4 \end{matrix} \right.
    where b∈Rb \in R. If ff is continuous at x=4x = 4, then which of the following statements is NOT true?

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