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Differentiable function from a functional equation in f(x + y)

This type of question, asked 4 times: 2021 Paper 10, 26 Jun 2022, 29 Jan 2023, 22 Jan 2025. All 4 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 10

    87
    Let f:R→Rf:R \rightarrow R satisfy the equation f(x+y)=f(x)⋅f(y)f(x + y) = f(x)\cdot f(y) for all x,y∈Rx,y \in R and f(x)≠0f(x) \neq 0 for any x∈Rx \in R. If the function ff is differentiable at x=0x = 0 and f′(0)=3f'(0) = 3, then lim⁡h→01h(f(h)−1)\lim_{h\rightarrow 0} \frac{1}{h}\left(f(h) - 1\right) is equal to
  2. Question 2

    26 Jun 2022

    171
    Let f:R→Rf:R \rightarrow R satisfy f(x+y)=2xf(y)+4yf(x),∀xf(x + y) =2^{x}f(y) +4^{y}f(x),\forall x, y∈Ry \in R. If f(2)=3f(2) = 3, then 14⋅f′(4)f′(2)14 \cdot\frac{f^{'}(4)}{f^{'}(2)} is equal to
  3. Question 3

    29 Jan 2023

    82
    Let f:R→Rf:R \rightarrow R be a differentiable function that satisfies the relation f(x+y)=f(x)+f(y)−f(x + y) = f(x) + f(y) - 1,∀x,y∈R1,\forall x,y \in R If f′(0)=2f^{'}(0) = 2, then ∣f(−2)∣|f( - 2)| is equal to
  4. Question 4

    22 Jan 2025

    66
    Let f(x)f(x) be a real differentiable function such that f(0)=1f(0) = 1 and f(x+y)=f(x)f′(y)+f′(x)f(y)f(x + y) = f(x)f^{'}(y) +f^{'}(x)f(y) for all x,y∈Rx,y \in R. Then ∑n=1100log⁡ef(n)\sum_{n = 1}^{100} \log_{e}f(n) is equal to :

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