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Second derivative of x^x type functions

This type of question, asked 2 times: 27 Jun 2022, 1 Feb 2023. All 2 questions below, oldest first.

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  1. Question 1

    27 Jun 2022

    176
    If y(x)=(xx)x, x>0y(x)=\left(x^{x}\right)^{x},\ x>0, then d2xdy2+20\dfrac{d^{2}x}{dy^{2}}+20 at x=1x=1 is equal to:

  2. Question 2

    1 Feb 2023

    165
    If y(x)=xx,x>0y(x) =x^{x},x> 0, then y′′(2)−2y′(2)y^{''}(2) - 2y^{'}(2) is equal to :

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