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Integral of ((x/a)^x + (a/x)^x) times log x: find the antiderivative

The same question, asked 2 times: 8 Apr 2023*, 10 Apr 2023. Every wording below, oldest first.

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  1. Question 1

    8 Apr 2023

    160
    The integral ∫((x2)x+(2x)x)log⁡2xdx\int\left( \left( \frac{x}{2} \right)^{x}+\left( \frac{2}{x} \right)^{x} \right)\log_{2}xdx is equal to

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  2. Question 2

    10 Apr 2023

    153
    For, α,β,γ,δ∈N\alpha,\beta,\gamma,\delta \in N, if ∫((xe)2x+(ex)2x)log⁡exdx=1α(xe)βx−1γ(ex)δx+C\int\left( \left( \frac{x}{e} \right)^{2x}+\left( \frac{e}{x} \right)^{2x} \right)\log_{e}xdx =\frac{1}{\alpha}\left( \frac{x}{e} \right)^{\beta x}-\frac{1}{\gamma}\left( \frac{e}{x} \right)^{\delta x}+ C, Where e=∑n=0∞1n!e =\sum_{n = 0}^{\infty} \frac{1}{n!} and CC is constant of integration, then α+2β+3γ−4δ\alpha + 2\beta + 3\gamma - 4\delta is equal to:

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