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Given the sum of (x_i - alpha), the sum of (x_i - beta)^2 and the standard deviation: find alpha and beta

The same question, asked 2 times: 2021 Paper 26*, 1 Feb 2024. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 26

    83
    Let X1,X2,………..X18X_{1},X_{2},\ldots\ldots\ldots..X_{18} be eighteen observation such that ∑i=118(Xi−α)=36\sum_{i = 1}^{18} \left( X_{i}- \alpha \right)= 36 and ∑i=118(Xi−β)2=90\sum_{i = 1}^{18} \left( X_{i}- \beta \right)^{2}= 90, where α\alpha and β\beta are distinct real numbers. If the standard deviation of these observations is 1 , then the value of ∣α−β∣|\alpha - \beta| is
  2. Question 2

    1 Feb 2024

    168
    Consider 10 observation x1,x2,…,x10x_{1},x_{2},\ldots,x_{10} such that ∑i=110(xi−α)=2\sum_{i = 1}^{10} \left( x_{i}- \alpha \right)= 2 and ∑i=110(xi−β)2=40\sum_{i = 1}^{10} \left( x_{i}- \beta \right)^{2}= 40, where α,β\alpha,\beta are positive integers. Let the mean and the variance of the observations be 65\frac{6}{5} and 8425\frac{84}{25} respectively. Then βα\frac{\beta}{\alpha} is equal to:

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