PYQ Vault

Sums of (x_i - a) or (x_i - a)^2 about given points: find the mean, variance or the constants

This type of question, asked 6 times: 2021 Paper 26, 29 Jul 2022, 1 Feb 2024, 29 Jan 2025, 4 Apr 2026 S2, 6 Apr 2026 S1. All 6 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 26

    83
    Let X1,X2,………..X18X_{1},X_{2},\ldots\ldots\ldots..X_{18} be eighteen observation such that ∑i=118(Xi−α)=36\sum_{i = 1}^{18} \left( X_{i}- \alpha \right)= 36 and ∑i=118(Xi−β)2=90\sum_{i = 1}^{18} \left( X_{i}- \beta \right)^{2}= 90, where α\alpha and β\beta are distinct real numbers. If the standard deviation of these observations is 1 , then the value of ∣α−β∣|\alpha - \beta| is
  2. Question 2

    29 Jul 2022

    82
    Let the mean and the variance of 20 observations x1,x2,…x20x_{1},x_{2},\ldots x_{20} be 15 and 9 , respectively. For α∈R\alpha \in R, if the mean of (x1+α)2,(x2+α)2,…,(x20+α)2\left( x_{1}+ \alpha \right)^{2},\left( x_{2}+ \alpha \right)^{2},\ldots,\left( x_{20}+ \alpha \right)^{2} is 178 , then the square of the maximum value of α\alpha is equal to
  3. Question 3

    1 Feb 2024

    168
    Consider 10 observation x1,x2,…,x10x_{1},x_{2},\ldots,x_{10} such that ∑i=110(xi−α)=2\sum_{i = 1}^{10} \left( x_{i}- \alpha \right)= 2 and ∑i=110(xi−β)2=40\sum_{i = 1}^{10} \left( x_{i}- \beta \right)^{2}= 40, where α,β\alpha,\beta are positive integers. Let the mean and the variance of the observations be 65\frac{6}{5} and 8425\frac{84}{25} respectively. Then βα\frac{\beta}{\alpha} is equal to:

    Tap an option to check your answer.

  4. Question 4

    29 Jan 2025

    68
    Let x1,x2,……x10x_{1},x_{2},\ldots\ldots x_{10} be ten observations such that ∑i=110(xi−2)=30,∑i=110(xi−β)2=98,β>2\sum_{i = 1}^{10} \left( x_{i}- 2 \right)= 30,\sum_{i = 1}^{10} \left( x_{i}- \beta \right)^{2}= 98,\beta > 2 and their variance is 45\frac{4}{5}. If μ\mu and σ2\sigma^{2} are respectively the mean and the variance of 2(x1−1)+4β,2(x2−1)+2\left( x_{1}- 1 \right)+ 4\beta,2\left( x_{2}- 1 \right)+ 4β,….,2(x10−1)+4β4\beta,\ldots.,2\left( x_{10}- 1 \right)+ 4\beta, then βμσ2\frac{\beta\mu}{\sigma^{2}} is equal to :

    Tap an option to check your answer.

  5. Question 5

    4 Apr 2026 S2

    58
    For 10 observations x1,x2,….,x10x_{1},x_{2},\ldots.,x_{10}, if ∑i=110(xi+2)2=180\sum_{i = 1}^{10} \left( x_{i}+ 2 \right)^{2}= 180 and ∑i=110(xi−1)2=90\sum_{i = 1}^{10} \left( x_{i}- 1 \right)^{2}= 90, then their standard deviation is :

    Tap an option to check your answer.

  6. Question 6

    6 Apr 2026 S1

    59
    A data consists of 20 observations x1,x2,…..,x20x_{1},x_{2},\ldots..,x_{20}. If ∑i=120(xi+5)2=2500\sum_{i= 1}^{20} \left( x_{i}+ 5 \right)^{2}= 2500 and ∑i=120(xi−5)2=100\sum_{i= 1}^{20} \left( x_{i}- 5 \right)^{2}= 100, then the ratio of mean to standard deviation of this data is :

    Tap an option to check your answer.