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Triangle from the midpoints of its sides

This type of question, asked 2 times: 2021 Paper 24, 2 Apr 2026 S1. All 2 questions below, oldest first.

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  1. Question 1

    2021 Paper 24

    84
    Let the points of intersection of the lines x−y+1=0x-y+ 1 = 0, x−2y+3=0x- 2y+ 3 = 0 and 2x−5y+11=02x- 5y+ 11 = 0 be the mid points of the sides of a triangle ABCABC. Then the area of the triangle ABCABC is

  2. Question 2

    2 Apr 2026 S1

    59
    Let the mid points of the sides of a triangle ABCABC be (52,7),(52,3)\left( \frac{5}{2},7 \right),\left( \frac{5}{2},3 \right) and (4,5)(4,5). If its incentre is (h,k)(h,k), then 3 h+k3\text{ }h + k is equal to :

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