Least n for which a trig equation has exactly k solutions in [0, n pi/2]
This type of question, asked 2 times: 27 Jan 2024, 30 Jan 2024. All 2 questions below, oldest first.
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Question 1
27 Jan 2024
165If 2tan2θ−5secθ=1 has exactly 7 solutions in the interval [0,2nπ], for the least value of n∈N then ∑k=1n2kk is equal to :
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Question 2
30 Jan 2024
79If 2sin3x+sin2xcosx+4sinx−4=0 has exactly 3 solutions in the interval [0,2nπ],n∈N, then the roots of the equation x2+nx+(n−3)=0 belong to :
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