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Four points with given position vectors or coordinates are coplanar: find the unknown

This type of question, asked 4 times: 2021 Paper 25, 29 Jul 2022, 25 Jan 2023, 6 Apr 2023. All 5 questions below, oldest first.

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  1. Question 1

    2021 Paper 25

    78
    If (1,5,35),(7,5,5),(1,λ,7)(1,5,35),(7,5,5),(1,\lambda,7) and (2λ,1,2)(2\lambda,1,2) are coplanar, then the sum of all possible values of λ\lambda is:

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  2. Question 2

    29 Jul 2022

    165
    If (2,3,9),(5,2,1),(1,λ,8)(2,3,9),(5,2,1),(1,\lambda,8) and (λ,2,3)(\lambda,2,3) are coplanar, then the product of all possible values of λ\lambda is:

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  3. Question 3

    25 Jan 2023

    152
    If the four points, whose position vectors are 3i^−4j^+2k^,i^+2j^−k^,−2i^−j^+3k^3\widehat{i}- 4\widehat{j}+ 2\widehat{k},\widehat{i}+ 2\widehat{j}-\widehat{k}, - 2\widehat{i}-\widehat{j}+ 3\widehat{k} and 5i^−2αj^+4k^5\widehat{i}- 2\alpha\widehat{j}+ 4\widehat{k} are coplanar, then α\alpha is equal to

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  4. Question 4

    6 Apr 2023

    157
    The sum of all values of α\alpha, for which the points whose position vectors i^−2j^+3k^,2i^−3j^+4k^\widehat{i}- 2\widehat{j}+ 3\widehat{k},2\widehat{i}- 3\widehat{j}+ 4\widehat{k}, (α+1)i^+2k^(\alpha + 1)\widehat{i}+ 2\widehat{k} and 9i^+(α−8)j^+6k^9\widehat{i}+ (\alpha - 8)\widehat{j}+ 6\widehat{k} are coplanar, is equal to

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  5. Question 5

    6 Apr 2023

    79
    Let the position vectors of the points A,B,CA,B,C and DD be 5i^+5j^+2λk^,i^+2j^+3k^,−2i^+λj^+4k^5\widehat{i}+ 5\widehat{j}+ 2\lambda\widehat{k},\widehat{i}+ 2\widehat{j}+ 3\widehat{k}, - 2\widehat{i}+ \lambda\widehat{j}+ 4\widehat{k} and −i^+5j^+6k^-\widehat{i}+ 5\widehat{j}+ 6\widehat{k}. Let S={λ∈R:S=\{\lambda\in R: the points A,B,CA,B,C and DD are coplanar}\}. Then ∑λ∈S(λ+2)2\sum_{\lambda \in S} (\lambda + 2)^{2} is equal to

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