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Day 197: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    Motion in a Straight Line. Asked once: 2021 Paper 21 (same type asked 3 times) See all 3 of this type

    4
    Water drops are falling from a nozzle of a shower onto the floor, from a height of 9.8 m9.8\text{ }m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.

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  2. Question 2

    Oscillations. Asked once: 30 Jan 2023 (same type asked 3 times) See all 3 of this type

    21
    The general displacement of a simple harmonic oscillator is x=Asinωtx = Asin\omega t. Let TT be its time period. The slope of its potential energy (U) - time ( tt ) curve will be maximum when t=Tβt =\frac{T}{\beta}. The value of β\beta is

  3. Question 3

    Motion in a Straight Line. Asked once: 2021 Paper 10 (same type asked 3 times) See all 3 of this type

    7
    The velocity-displacement graph of a particle is shown in the figure. The acceleration-displacement graph of the same particle is represented by:

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  4. Question 4

    System of Particles and Rotational Motion. Asked once: 22 Jan 2026 S2 (same type asked 3 times) See all 3 of this type

    22
    Two masses m and 2 m are connected by a light string going over a pulley (disc) of mass 30 m with radius r=0.1 mr = 0.1\text{ }m. The pulley is mounted in a vertical plane and it is free to rotate about its axis. The 2 m mass is released from rest and its speed when it has descended through a height of 3.6 m is ____\_\_\_\_ m/sm/s. (Assume string does not slip and  g=10 m/s2)\left. \ g = 10\text{ }m/s^{2} \right)

  5. Question 5

    Thermodynamics. Asked once: 11 Apr 2023 (same type asked 3 times) See all 3 of this type

    10
    1 kg1\text{ }kg of water at 100∘C100^{\circ}C is converted into steam at 100∘C100^{\circ}C by boiling at atmospheric pressure. The volume of water changes from 1.00×10−3 m31.00 \times10^{- 3}{\text{ }m}^{3} as a liquid to 1.671 m31.671{\text{ }m}^{3} as steam. The change in internal energy of the system during the process will be (Given latent heat of vaporisation =2257 kJ/kg= 2257\text{ }kJ/kg. Atmospheric pressure =1×105 Pa= 1 \times10^{5}\text{ }Pa )

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